Part A:SA = 3.14(rs + r^2)SA = 3.14((2)(3) + (2)^2)
Part B:SA = 3.14((2)(3) + (2)^2)SA = 3.14(6 + 4)SA = 3.14(10)SA = 31.4SA = 31.4 units^2
Answer:
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the given information,
x2 = - 1
x1 = 4
y2 = 6
y1 = 3
Therefore,
Distance = √(- 1 - 4)² + (6 - 3)²
Distance = √(- 5² + 3²) = √(25 + 9) = √34
Distance = 5.83
The value of the X must be 74 in. ..
<span>x(a+b)=xa+xb</span>.
<span>4(3+7)</span>
<span><span>4∗3+4∗7</span>
Please=Parentheses
Excuse=Exponents
My=Multiply
Dear=Divide
Aunt=Add
Sally-Subtract
</span>
Answer:
4. 3,4
5. 0,4
6. -8, -1
Hope that helps!
Step-by-step explanation:
