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3 years ago

Please answer correctly

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

Graph B

Step-by-step explanation:

the "x" and "y" represent $\frac{rise}{run}$

so therefore, it's $\frac{-2}{-2}$ , $\frac{-1}{-1}$ , $\frac{1}{1}$ , $\frac{2}{2}$

you would start at (0,0) or the origin

and count over one and up one, or however many units the fraction/chart tells you to count up

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Help please :c!

LUCKY_DIMON [66]

Answer:

see the procedure

Step-by-step explanation:

we know that

m∠1+m∠2=180° -----> supplementary angles (form a linear pair)

we have

m∠1=27° ----> given problem

substitute the measure of m∠1 in the equation above and solve for m∠2

27°+m∠2=180°

Subtract 27° both sides

27°+m∠2-27°=180°-27° ----> by subtraction property of equality

m∠2=153°

4 0

3 years ago

Graph the given function.

SpyIntel [72]

*<em>The graph has an asymptote at y = 0 and is increasing as x approaches positive infinity.*</em>

(got it right on edmentum)

<h2>for your assurance please look at the picture below for the right answer↓</h2>

4 0

2 years ago

Using addition formula solve tan 15

salantis [7]

Answer:

2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = $\frac{tanA-tanB}{1+tanAtanB}$ and the exact values

tan45° = 1 , tan60° = $\sqrt{3}$ , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

= $\frac{\sqrt{3}-1 }{1+\sqrt{3} }$

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

= 2 - $\sqrt{3}$

3 0

3 years ago

Graph the function.<br> y=-x-6 ifx<-6<br> y = 2x + 12 if x>-6

Naddik [55]

Answer:

see attached

Step-by-step explanation:

For x < -6, the function has a slope of -1 and an x-intercept of -6.

For x > -6, the function has a slope of 2 and an x-intercept of -6.

The function given here is not defined at x=6, so there is a hole at (-6, 0).

7 0

3 years ago

10 POINTS! PLEASE HELP!! The illustration shows a compact disc tray that holds five CDs. The radius of each compact disc is 9 cm

MariettaO [177]

We can see that there are 5 CDs, each of radius 9 cm

<u>Area occupied by 1 disc:</u>

Area of a circle = πr²

Area of disc = π(9)²

Area of disc = 3.14 * 81 = 254 cm²

<u>Area occupied by 5 discs:</u>

Area occupied by 5 discs = Area occupied by 1 disc * 5

Area occupied by 5 discs = 254 * 5

Area occupied by 5 discs = 1270 cm²

3 0

2 years ago