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Lostsunrise [7]
3 years ago
12

Find the area of the rhombus

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Check the picture below.

since in a rhombus the diagonals bisect each other, thus EC = EA.

now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus

\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}

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In ΔFGH, f = 37 cm, ∠F=28° and ∠G=124°. Find the length of g, to the nearest 10th of a centimeter.
MatroZZZ [7]

Answer:

  65.3 cm

Step-by-step explanation:

The law of sines can be used for this.

  g/sin(G) = f/sin(F)

  g = (37 cm)sin(124°)/sin(28°) ≈ 65.3 cm . . . . multiply by sin(G)

The length of g is about 65.3 cm.

6 0
3 years ago
You have a 5-question multiple-choice test. Each question has four choices. You don’t know any of the answers. What is the exper
lana66690 [7]
2 out of 5 chance that you will attests get 3
4 0
3 years ago
WILL GIVE BRAINLEIST
DanielleElmas [232]

Answer: Last option ("Each term in the second sequence is one-third the corresponding term in the first sequence.")

Explanation:

First, you need to understand what the rules are saying. I find it useful to write them as equations, but everyone's different. Especially for this situation, making a table should be really helpful.

Rule 1: add 6 starting from 0

Add 6 each time. The "add" part should tell you that it's the slope. The equation has a slope of 6. "Starting from 0" tells you that the y-intercept is 0. Using slope-intercept form (y=mx+b, where m is the slope and b is the y-intercept), you can write the equation as y=6x+0, or y=6x.

Rule 2: add 2 starting from 0

2 is the slope and 0 is the y-intercept. y=2x

You didn't <em>have</em> to do this part, but it makes the rules easier to understand. Now you can easily make a table to find the relationship between the rules. First, pick some values of x to use:

Rule 1:

x  |    1   |   2  |   3

y  |         |       |

Rule 2:

x  |    1   |   2  |   3

y  |         |       |

(They're supposed to be tables with only the x-values filled in.)

Using the equations, or only the rules, you can fill in the tables.

You can use more than 3 values of x, but I think this is enough.

x=1:

Rule 1: y=6x

             =6(1)

            =6

Rule 2: y=2x

              =2(1)

              =2

Do the same thing for y when x=2 and x=3. Then you can fill in the tables to get:

Rule 1:

x  |    1   |   2  |   3

y  |    6  |  12  |   18

Rule 2:

x  |    1   |   2  |   3

y  |    2  |   4  |   6

Since you've organized the values now, it'll be much simpler to find the relationship between the rules. Observe the y-values.

When x=1, rule 1 results in 6, and rule 2 results in 2. Now look at each option in the answers.

"Each term in the second sequence is three times the corresponding term in the first sequence."

In the first sequence, you have 6 when x=1. If the corresponding term in the second sequence has to be 3 times that, it would have to be 18. This one doesn't work.

"Each term in the first sequence is one-third the corresponding term in the second sequence."

This is saying the same thing as the previous option. It doesn't work.

"Each term in the first sequence is six times the corresponding term in the second sequence."

When x=1, y in the second sequence is 2. 6 times that is 12, but the value in the first sequence is only 6. This option is incorrect as well.

"Each term in the second sequence is one-third the corresponding term in the first sequence."

2/6=1/3, so this one does work. You could have arrivived at this conclusion earlier by just dividing, but I wanted to explain why the rest don't work.

Hope I could help!

4 0
3 years ago
Subtract 8 1/2 - 2 2/3 = ?
Andrews [41]

Answer: 2 2/3 or 2.6 repeating

Step-by-step explanation:

- Reduce the numbers With the greatest common divisor 2

- Calculate product

- Calculate the difference

- YOUR FINAL ANSWER

Hope I was able to satisfy your needs

8 0
3 years ago
Read 2 more answers
40% of the students passed both exams. 80% of the students passed the second exam. how many students (in percent) who passed the
navik [9.2K]

50%. students (in percent) who passed the second exam also passed the first exam.

Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.

Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.

Thus, both tests were passed by 40 of the 80 pupils who passed the second one:                                      

40/80 = 1/2 = 50%.

Find out more on Percentage at:

brainly.com/question/24877689

#SPJ4

7 0
1 year ago
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