The p-value of the test statistic from the standard normal table is 0.0017 which is less than the level of significance therefore, the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that less than 20% of the pumps are inaccurate.

Step-by-step explanation:

Here, 1304 gas pumps were not pumping accurately and 5689 pumps were accurate.

x = 1304, n = 1304 + 5689 = 6993

The level of significance = 0.01

The sample proportion of pump which is not pumping accurately can be calculated as,

The claim is that the industry representative less than 20% of the pumps are inaccurate.

The hypothesis can be constructed as:

H0: p = 0.20

H1: p < 0.20

The one-sample proportion Z test will be used.

The test statistic value can be obtained as:

$Z=\frac{\hat{p}-P}{\sqrt{\frac{P(1-P))}{n}}}\\\\Z=\frac{0.186-0.20}{6993}\\\\Z=-2.927$

5 0

2 years ago

It takes Christy 1.5 hours to clean the garage. It takes the kids 2 hours to clean the same garage. If they all clean together,

Alborosie

Christy c = 90 min

kids k = 120 min

total time t = ?

I would do : 90+120 = 210 then divide that by 2 which equals 105 min

6 0

2 years ago

Pls help oooooooooooo

Digiron [165]

Answer:

110

Step-by-step explanation:

Suppose lines EH and BD are parallel:

Angle <GFE and angle <ABC are supplementary so their sum is equal to 180

2x + 10 + x + 20 = 180 add like terms

3x + 30 = 180 subtract 30 from both sides

3x = 150 divide both sides by 3

x = 50

We are asked the value of <ACD

<ABD and <ACD are also supplementary so we can find the value od <ACD:

x + 20 + <ACD = 180 we know x = 50 so we can replace x with that

50 + 20 + <ACD = 180

70 + <ACD = 180 subtract 79 from both sides

<ACD = 110

3 0

1 year ago

Jacka and Jill are 28 miles apart on the same path. If Jack skateboards 4 miles per hour, and Jill bikes 6 miles per hour, How l

Alexeev081 [22]

Idk really know I just trying the get points

6 0

2 years ago

Read 2 more answers

0.5+a=3.2 Answer please ​

0.5+a=3.2 Answer please