Answer:
3cd+3 1/3c- 3d
Step-by-step explanation:
6 cd+ 3 c- 7 d- 3 cd+ 4d+ 1/3 c
6 cd - 3 cd = 3 cd First term
3c + 1/3c = 3 1/3c Second Term
4d - 7d = -3d Third Term
Combine all terms to get:
3cd+3 1/3c- 3d
Answer:
It would take 19 hours and 36 minutes until there are 1040 bacteria present.
Step-by-step explanation:
Given that in a lab experiment, 610 bacteria are placed in a petri dish, and the conditions are such that the number of bacteria is able to double every 23 hours, to determine how long would it be, to the nearest tenth of an hour, until there are 1040 bacteria present, the following calculation must be performed:
610X = 1040
X = 1040/610
X = 1.7049
2 = 23
1.7049 = X
1.7049 x 23/2 = X
39.2131 / 2 = X
19.6 = X
100 = 60
60 = X
60 x 60/100 = X
36 = X
Therefore, it would take 19 hours and 36 minutes until there are 1040 bacteria present.
equation csn be represented as
money left = 500 - (n-1)×4.65
so we can see in first week money left
= 500 - (1-1)×4.65= 500-0=500
which is true because first week chaya got gift card and does not spend any money.
now lets assume that on week n money left is 327.95
so by equation
500 -(n-1)×4.65 = 327.95
500- 327.95 =( n-1)× 4.65
n -1 = 172.05/4.65=37
n = 37+1 = 38
in 38th week money left would be 327.95
Answer: A. 9567m
i hope i'm correct let me know if i'm wrong
Answer:
DE = 5
BC = 10
Step-by-step explanation:
ΔAED is a right triangle with legs of 4 and 6/2 = 3
Use the Pythagorean theorem to find DE
16 + 6 = 25 = 
DE = 5
The midsegment of a triangle is 1/2 the length of the corresponding side.
Therefore, BC = 2 DE = 2(5) = 10 = BC
