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lozanna [386]
3 years ago
13

Which statement is true

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer: B


Step-by-step explanation:


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EXPERT HELP AND EXPLAIN THE ANSWER :Caleb throws a ball three times for his dog Leo. For each throw, Leo either
schepotkina [342]
C makes the most sense
7 0
3 years ago
Factor completely 5xy3 15x3y2 − 30x2y2. 5(xy3 3x3y2 − 6x2y2) 5x(y3 3x2y2 − 6xy2) 5xy2(y 3x2 − 6x) Prime.
Mandarinka [93]

Factoring an expression involves rewriting the expression in simplier form

The factored expression of 5xy^3 + 15x^3y^2 - 30x^2y^2 is 5xy^2(y + 3x^2 - 6x)

<h3>How to factor the expression</h3>

The expression is given as:

5xy^3 + 15x^3y^2 - 30x^2y^2

Factor out 5x from the expression

5x(y^3 + 3x^2y^2 - 6xy^2)

Factor out y^2 from the expression

5xy^2(y + 3x^2 - 6x)

Hence, the factored expression of 5xy^3 + 15x^3y^2 - 30x^2y^2 is 5xy^2(y + 3x^2 - 6x)

Read more about factorized expressions at:

brainly.com/question/723406

3 0
3 years ago
Please help me .. thank you ​
KiRa [710]

Step-by-step explanation:

Break down every term into prime factors. ...

Look for factors that appear in every single term to determine the GCF. ...

Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...

Multiply out to simplify each term.

5 0
3 years ago
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HELP WILL GIVE BRAINLIEST
sweet [91]

Answer:

240 miles

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8 miles

Step-by-step explanation:

You cannot compare miles to miles. This makes this answer invalid and it is not a rate.

4 0
3 years ago
Simplify the given expression. Assume that no variable equals 0. (14x20y10 / 28x12y14)4
liq [111]

Answer:

\frac{1}{2^{4}*14^{3} *x^{28}*y^{46}}

Step-by-step explanation:

To simplify the expression \frac{14x^{20}y^{10}}{(2*14*x^{12} y^{14} )^{4}} first we need to raise every member of the denominator to the given exponent, number 4

Remember that (x^{b} )^{c} =z^{b*c} where 'a' and 'b are natural numbers (any numbers you want

\frac{14x^{20}*y^{10}}{2^{4}*14^{4}*x^{48}*y^{56}}

Where we can make some operations, remember that \frac{x^{a} }{x^{c} }=x^{a-c}

\frac{1}{2^{4}*14^{3} *x^{28}*y^{46}}

We have assumed that nor x, nor y equals 0 in any moment, since if that would happen, we ca not simplify anything bacause error math 0/0.

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4 years ago
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