Answer:
(2x^2 + x-3)/(4x^2-9)
Step-by-step explanation:
The denominator looks like an expression in which we have applied the difference of two squares to
In that case, we know that;
a^2-b^2 = (a-b)(a+ b)
That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;
(2x + 3)(2x-3) = 4x^2 - 9
Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial
That means;
(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3
So we have the original expression as;
(2x^2 + x-3)/(4x^2-9)
The distributive property says that a(b+c)= ab+ac
3(2y-7)= 3(2y)+ 3(-7)
Final answer: 6y-21
<span>Round 155 016 to the nearest thousand.
Let us first identify the place value of each digits
=> 6 = ones
=> 1 = tens
=> 0 = hundreds
=> 5 = thousands
=> 5 = ten thousands
=> 1 = hundred thousands
Now, the situation is asking to round to the nearest thousand
=> 155 016 is equals to 155 000 when rounded to the nearest thousand
because the number next to thousands is 0, and 0 is below 5 so apply rounding
down.</span>
Answer:
2/130 or 1/65
Step-by-step explanation:
64+4+2+60 (all the people) =130
Given the fact that ''2 learners studied but failed the test.'' Brian is the same.
So you would do 2/130 or simplify it, 1/65.
Hope it helps :)
