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mr Goodwill [35]
3 years ago
8

I wrote an equation using parentheses,brackets and braces with an answer of 268.What might the equation been

Mathematics
1 answer:
mote1985 [20]3 years ago
8 0
{2×[20×5]+68} could be your answer because 20×5 is 100 and 2×100 is 200. 200+68 is 268
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Please help with the answers and explain the process
N76 [4]

Step-by-step explanation:

multiply the denominator with the mixed number then add the numenator

4 × 2 +1 /4

= 8 + 1/4

= 9/4

again for mixed fraction

divide the numenator by denominator and put the quotient in the front side and remaining in numenator

13/7

= quotient = 1 , remaining = 6

  • answer = (1) 6/7
4 0
3 years ago
What is the sum of 7/13 and 11/26? Please help!!
Helga [31]

Answer:

The sum of 7/13 and 11/26 is 25/26.

Step-by-step explanation:

7/13 + 11/26

The common denominator is 26

7/13 *2/2 +11/26

14/26 + 11/26

25/26

8 0
3 years ago
Please help me ASAP for 10 points ❤️
PilotLPTM [1.2K]

3rd option is the answer

Photo attached for explanation.

7 0
4 years ago
Hii please help i’ll give brainliest if you give a correct answer. show your reasoning agree or not
iVinArrow [24]

Answer:

I Disagree cuz when you divide you are supposed to do it by flipping the numerator and denominator at the right and then multiply. So the correct answer should've been 4 and 1/2.

Now about that Brainly you promised...

6 0
3 years ago
How can I factorise (2x cubed - 5x + 3) ?
PilotLPTM [1.2K]
2x^3-5x+3=2x^3-2x-3x+3\\\\=2x(x^2-1)-3(x-1)\\\\=2x\underbrace{(x^2-1^2)}_{use\ (*)}-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\\\\=2x\underbrace{(x-1)}_{(**)}(x+1)-3\underbrace{(x-1)}_{(**)}\\\\=(x-1)[2x(x+1)-3]\\\\=(x-1)\underbrace{(2x^2+2x-3)}_{(***)}\\\\(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\\\\x=\frac{b^2\pm\sqrt{b^2-4ac}}{2a}

therefore\\x=\frac{-2\pm\sqrt{2^2-4(2)(-3)}}{2(2)}=\frac{-2\pm\sqrt{4+24}}{4}=\frac{-2\pm\sqrt{28}}{4}=\frac{-2\pm\sqrt{4\cdot7}}{4}=\frac{-2\pm2\sqrt7}{4}\\\\=\frac{-1\pm\sqrt7}{2}\\\\so,\ the\ answer:\\\\(x-1)\cdot2\left(x-\frac{-1-\sqrt7}{2}\right)\left(x-\frac{-1+\sqrt7}{2}\right)\\\\=\boxed{(x-1)(2x+1+\sqrt7)\left(x+\frac{1-\sqrt7}{2}\right)}=\boxed{\frac{1}{2}(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}
7 0
3 years ago
Read 2 more answers
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