Answer:
We are 95% confident that the average weight of the heaviest egg that is still medium size is 3.52 oz
Step-by-step explanation:
Mean = 3.2 oz, sd = 0.13 oz
Assuming there are 3 heavy eggs, n= 3, degree of freedom = n-1 = 3-1 = 2, t-value corresponding to 2 degrees of freedom and 95% confidence level is 4.303
Error margin = t×sd/√n = 4.303×0.13/√3 = 0.32 oz
Upper limit (heaviest egg that is still medium size) = mean + error margin = 3.2 + 0.32 = 3.52 oz
F x (x + h) - fx/h
fx +fh - fx /h
fh/h
f
So f is the answer
Answer: the answer is d
Step-by-step explanation:
The height should be C.) 400 mm. Hope this helps!! <3
