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kondaur [170]
3 years ago
13

Solve: |x + 9| User: Evaluate 5|7 - 9| - 2. -12 0 1 8

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0
Solve:

[x+9] - there is nothing to simplify

======================================

Evaluate:

5(7-9)-2

= 
35 -45-2

= -10-2

= -12

or

5(7-9)-2

= 
35 -45-2

= 35-47

= -12
------------------------------------------
So, -12 is the answer.
AlexFokin [52]3 years ago
8 0

I believe it is 8. Sorry if I´m wrong.

You might be interested in
-40+2n=4n-8n+8 EXPLAIN IN NUMBER FORM AND NO WORDS
marin [14]

Answer:

−40+2n=−4n+8

−40+2n+40=−4n+8+40

2n=−4n+48

2n+4n=−4n+48+4n

6n=48

answer:  n=8

Step-by-step explanation:

8 0
3 years ago
The owner of a factory wants to determine a confidence interval for the average wages at his factory. The population average wag
iVinArrow [24]

4,034.06 ,5,965.94 are confidence interval for the population average wages at the factory.

What is confidence interval estimation?

Your estimate's mean plus and minus the range of that estimate's fluctuation is called a confidence interval.

                                              If you repeat your test, you can expect your estimate to fall between these numbers with a reasonable degree of certainty.  Another term for probability in statistics is confidence.

The formula for confidence interval estimation is:

μ = M ± Z(sM)

where:

M = sample mean

Z = Z statistic determined by confidence level

sM = standard error = √(s2/n)

M = 50000

Z = 2.58

sM = √(30002/64) = 375

μ = M ± Z(sM)

μ = 50000 ± 2.58*375

μ = 50000 ± 965.94

μ = 4,034.06 ,5,965.94

Learn more about confidence interval

brainly.com/question/24131141

#SPJ1

6 0
1 year ago
What is the distance between the points (7 , 31) and (7 , 19) in the coordinate plane?
Tresset [83]

12

.........................

8 0
3 years ago
A) In 2000, the population of a country was approximately 5.82 million and by 2040 it is projected to grow to 9 million. Use the
mezya [45]

Answer:

By 2086

Step-by-step explanation:

The provided equation is:

A=A0*e^{k*t} , where:

A=total of population after t years

A0=initial population

k= rate of growth

t= time in years

Given information:

The final population will be 15 million, then A=15.

We start in 2000 with a 5.82 million population, then A0=5.82.

Missing information:

Although k is not given, we can calculate k by using the following statement, from 2000 to 2040 (within 40 years) population is proyected to grow to 9 million, which means a passage from 5.8 to 9 million (3.2 million increament).

Then we can use the same expression to calculate k:

A=A0*e^{k*t}

9=5.8*e^{40*k}

ln(9/5.8)/40=k

0.010984166494596147=k

0.011=k

Now that we have k=0.011, we can find the time (t) by which population will be 15 million:

A=A0*e^{k*t}

15=5.8*e^{0.011t}

ln(15/5.8)/0.011=t

86.38111668634878=t

86.38=t

Because the starting year is 2000, and we need 86.38 years for increasing the population from 5.8 to 15 million, then by 2086 the population will be 15 million.

4 0
3 years ago
Jen ran 9 miles in 117 minutes , if her speed remained the same throughout the run , what was her pace?
S_A_V [24]
117 ÷ 9 = 13

Hope this helps!
5 0
3 years ago
Read 2 more answers
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