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Phantasy [73]
3 years ago
8

What is the generalized vertex form of a quadratic equation

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola.

Step-by-step explanation:

You might be interested in
17. For the parallelogram, find the value of the variables. Show your work. 5x + 2 3y - 6 21 17 24=3y-6 => 30=3y, y=10, 12 =
Dafna11 [192]
In this problem, you have already shown the solution.

24 = 3y - 6 => 30 = 3y, y =10

12 = 5x + 2 => 10 = 5x , x = 2

And yes, basically parallel sides must have the same length

These are the answers:

for 17.) x = 2
y = 10

for 18.) mid segment = (side 1 + side 2) / 2 -->
19 = (24 + side2) / 2 -->
38 = 24 + side2,

thus, side 2 = 14 units
3 0
3 years ago
Using linked lists or a resizing array; develop a weighted quick-union implementation that removes the restriction on needing th
balu736 [363]

Answer:

Step-by-step explanation:

package net.qiguang.algorithms.C1_Fundamentals.S5_CaseStudyUnionFind;

import java.util.Random;

/**

* 1.5.20 Dynamic growth.

* Using linked lists or a resizing array, develop a weighted quick-union implementation that

* removes the restriction on needing the number of objects ahead of time. Add a method newSite()

* to the API, which returns an int identifier

*/

public class Exercise_1_5_20 {

public static class WeightedQuickUnionUF {

private int[] parent; // parent[i] = parent of i

private int[] size; // size[i] = number of sites in subtree rooted at i

private int count; // number of components

int N; // number of items

public WeightedQuickUnionUF() {

N = 0;

count = 0;

parent = new int[4];

size = new int[4];

}

private void resize(int n) {

int[] parentCopy = new int[n];

int[] sizeCopy = new int[n];

for (int i = 0; i < count; i++) {

parentCopy[i] = parent[i];

sizeCopy[i] = size[i];

}

parent = parentCopy;

size = sizeCopy;

}

public int newSite() {

N++;

if (N == parent.length) resize(N * 2);

parent[N - 1] = N - 1;

size[N - 1] = 1;

return N - 1;

}

public int count() {

return count;

}

public int find(int p) {

// Now with path compression

validate(p);

int root = p;

while (root != parent[root]) {

root = parent[root];

}

while (p != root) {

int next = parent[p];

parent[p] = root;

p = next;

}

return p;

}

// validate that p is a valid index

private void validate(int p) {

if (p < 0 || p >= N) {

throw new IndexOutOfBoundsException("index " + p + " is not between 0 and " + (N - 1));

}

}

public boolean connected(int p, int q) {

return find(p) == find(q);

}

public void union(int p, int q) {

int rootP = find(p);

int rootQ = find(q);

if (rootP == rootQ) {

return;

}

// make smaller root point to larger one

if (size[rootP] < size[rootQ]) {

parent[rootP] = rootQ;

size[rootQ] += size[rootP];

} else {

parent[rootQ] = rootP;

size[rootP] += size[rootQ];

}

count--;

}

}

public static void main(String[] args) {

WeightedQuickUnionUF uf = new WeightedQuickUnionUF();

Random r = new Random();

for (int i = 0; i < 20; i++) {

System.out.printf("\n%2d", uf.newSite());

int p = r.nextInt(i+1);

int q = r.nextInt(i+1);

if (uf.connected(p, q)) continue;

uf.union(p, q);

System.out.printf("%5d-%d", p, q);

uf.union(r.nextInt(i+1), r.nextInt(i+1));

}

}

}

8 0
3 years ago
Mario has $14.35 left it as wallet.
konstantin123 [22]

Answer:

Approximately $255

Step-by-step explanation:

If we need to find how much money Mario had before he spent money, we would have to add the prices that he spent to 14.35.

14.35 + 148.43 + 92.05 = 254.83 ≈ 255

Mario should of started out with $254.83 in his wallet.

4 0
3 years ago
How could you determine one-fourth the length of a segment
Elza [17]
Divide the length of the segment by 4 
8 0
3 years ago
Harold Wagner pays a $325.00 premium annually. This represents 40% of the total premium. The rest of the premium is paid by his
tigry1 [53]

Answer:

a). The company's percentage=60%

b). The total premium=$812.50

c). The company's payment=$487.50

Step-by-step explanation:

a).

The total premium can be expressed as;

T=H+R

where;

T=proportion of total premium

H=proportion paid by Harold Wagner

R=remaining proportion

In our case;

T=100%

H=40%

R=r

replacing;

100%=40%+r

r=100%-40%

r=60%

The company's percentage=60%

b).

The total premium, if 40%=$325.00

Let total premium be=t

40% of t=325

(40/100)×t=325

0.4 t=325

t=325/0.4

t=$812.50

The total premium=$812.50

c).

The company's payment=60% of total premium

The company's payment=(60/100)×812.5

The company's payment=$487.50

5 0
4 years ago
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