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choli [55]
3 years ago
10

Which expression is equivalent to -36 – 8?

Mathematics
2 answers:
Ber [7]3 years ago
8 0
Answer is B I got it right on the test :)

Volgvan3 years ago
5 0

Answer:B

Step-by-step explanation:

-36 – 8=-44

36+8=44

-36 + (-8)=-44

8 – 36=-28

-8+36=28

As you can see only B equals -44 just like the expression given,

Hope my explanation helps

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Find the least common denominator of 11/ 70 and 7 /60 . LCD =
drek231 [11]

The least common denominator is 420

<h3>How to find the least common denominator?</h3>

The expressions are given as:

11/70 and 7/60

Factorize the denominator of the fractions.

So, we have

70 = 7 * 10

60 = 6 * 10

Multiply the factors

LCD = 6 * 7 * 10

Evaluate

LCD = 420

Hence, the least common denominator is 420

Read more about least common denominator at

brainly.com/question/22721226

#SPJ1

5 0
2 years ago
Could anyone help me plz what is the square root of 25?
WINSTONCH [101]
The square root of 25 is 5
3 0
4 years ago
Read 2 more answers
Just want to know if this is right...
raketka [301]
Sorry, your answer isn't correct.
The answer is 7.
4(7)+15(7)+3+7(7)-5=180

28  + 108 +  45 = 180.


If we plug in 22.5, it will equal 583 not 180.
we will get 


3 0
3 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
£6846 is shared equally between 7 people. How much does each person get?
jok3333 [9.3K]

Answer:

£978

Step-by-step explanation:

i did use a calculator so i don't know if this is wrong or not, sorry if it is.

8 0
3 years ago
Read 2 more answers
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