Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
They do not appear to be symmectric. they seem to line up well
I believe C and E, because in C, he puts in 600 then takes out 600, which equals 0. in E, they get 3000 and then spend the 3000, which also equals 0.
Answer:%28a-b%29%2Fb=c
a-b=bc
a=bc%2Bb
a=b%28c%2B1%29
a%2F%28c%2B1%29=b
b=a%2F%28c%2B1%29
So the answer is b=a%2F%28c%2B1%29
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3x-x+2=4
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Step-by-step explanation: