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Dovator [93]
3 years ago
10

How can scientists use the following pedigree?

Mathematics
1 answer:
kolezko [41]3 years ago
3 0
The answer is C because you can see the different types of forms and colors which shows dominance
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Nikki, Kylie and Andy are arguing about who has the biggest candy bar. Below are their measurements of each candy bar:
saveliy_v [14]

Answer:

Andy.  

Step-by-step explanation:

10 is greater than 9.99 by 0.01.  10 is also greater than 1.999 by 8.001

6 0
3 years ago
Read 2 more answers
Which equation represents the line that passes through the point (1,5) And has a slope of -2?
posledela

The correct answer would be A.

We can immediately eliminate C and D because they have the slope listed as 2 rather than -2.

Because we're looking for the line that passes through (1, 5), we know that the y-intercept has to be 7, because from (0, 7) we get to (1, 5) when we apply the slope of -2.

Thus, the answer is A.

3 0
3 years ago
Solve the system of linear equations by elimination. x+6y=28 2x−3y=−19
bekas [8.4K]
The answer is: x = -4 and y = 11/3
8 0
3 years ago
Match the following unit volumes with the most appropriate converted unit volume:
Xelga [282]
2.64 gal-10 liters
0.14 cubic meters -5 cubic feet
5.35 cubic meters- 7 cubic yards
6.34 pints=3 liters
8 0
4 years ago
use the definition of countinuity to find the value of k so that the function is continuous for all real numbers
liubo4ka [24]

First of all, recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

So if <em>x</em> < 4, then <em>x</em> - 4 < 0, so |<em>x</em> - 4| = -(<em>x</em> - 4), and the first case in <em>h(x)</em> reduces to

\dfrac{|x-4|}{x-4}=\dfrac{-(x-4)}{x-4} = -1

Next, in order for <em>h(x)</em> to be continuous at <em>x</em> = 4, the limits from either side of <em>x</em> = 4 must be equal and have the same value as <em>h(x)</em> at <em>x</em> = 4. From the given definition of <em>h(x)</em>, we have

h(4) = 5k-4\cdot4 = 5k-16

Compute the one-sided limits:

• From the left:

\displaystyle \lim_{x\to4^-}h(x) = \lim_{x\to4}\frac{|x-4|}{x-4} = \lim_{x\to4}(-1) = -1

• From the right:

\displaystyle \lim_{x\to4^+}h(x) = \lim_{x\to4}(5k-4x) = 5k-16

If the limits are to be equal, then

-1 = 5<em>k</em> - 16

Solve for <em>k</em> :

-1 = 5<em>k</em> - 16

15 = 5<em>k</em>

<em>k</em> = 3

3 0
2 years ago
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