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rosijanka [135]
3 years ago
13

X^2+(x-8)^2-3(x+2) = 2(x+9)

Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

There are two solutions:

x = 5/2 = 2.500

x = 8

Step-by-step explanation:

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Write an expression that is equivalent to 123x + x + 2x
Svetlanka [38]
This simplified is 126x so that is equivalent to this expression
7 0
3 years ago
If f(x) = -5x +5 and g(x) +3x +8, find g(f(x))
4vir4ik [10]

Answer:

Step-by-step explanation:

g(f(x)) =  g(f(x)) +3(-5x +5 ) +8

= -15x + 15 + 8

= -15x + 23

4 0
3 years ago
Given functions f ( x ) = 1 √ x and m ( x ) = x 2 − 4 , state the domains of the following functions using interval notation.
babunello [35]

The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) =  1/√x

m(x) = x² - 4

Domain of f(x)/m(x):

f(x)/m(x) = (1/√x)/(x² - 4)

f(x)/m(x) = 1/√x(x² - 4)

The denominator cannot be zero:

√x(x² - 4) ≠ 0

x(x - 2)(x+2) ≠ 0

x ≠ 0, 2, -2

and x > 0

Domain of f(x)/m(x) is:   (0, ∞) - {0, 2, -2} or \:\left(0,\:2\right)\cup \left(2,\:\infty \:\right)

Domain of f(m(x)):

f(m(x)) = 1/√(x² - 4)

x² - 4 > 0

Domain: \rm \left(-\infty \:,\:-2\right)\cup \left(2,\:\infty \:\right)

Domain of m(f(x)):

= ((1/√x)² - 4)

Domain: \:\left(0,\:\infty \:\right)

Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

7 0
2 years ago
One - eighth of 7.92 x 10^10
liraira [26]
The answer is 9900000000 (thats 8 zeros) What you do is you find 10^10 which is 10000000000 (ten zeros) and multiply that by 7.92 to get 79200000000 then you just multiply it by 1/8 to get the answer.
3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Olin [163]

Answer:

Step-by-step explanation:

in tri ADC and tri BDC

∠ADC =∠BDC = 90

DC is common

AD = BD (given)

triangle ADC ≅ tri BDC by SAS congruency

hence AC = BC by CPCT ( congruent parts of congruent triangles)

hence, BC = 13

8 0
3 years ago
Read 2 more answers
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