Answer:
Women who carry one copy of the mutated gene still have normal color vision because they have another copy, which is not mutated, in the other X chromosome that will be the dominant one. As a result, the women are carriers of the mutated gene but not color blind.
Explanation:
Colorblindness is a sex-linked mutation. A woman has two X chromosomes, while a man has one X chromosome and one Y chromosome. The mutated gene that causes color blindness is on the X chromosome, and it is OPN1LW. So if a woman has one mutated OPN1LW in one of her two X chromosomes, the OPN1LW gene in the other X chromosome will be the dominant one stopping the woman from being colorblind.
In the case of men, as they only have one X chromosome, if there is a mutation on the OPN1LW in the X chromosome, the men will be colorblind because there is no extra copy of the gene, as it is in women.
Answer:
Calcium is a chemical element with the symbol Ca and atomic number 20.
Explanation:
Manzanilla, hinojo, menta puperita, melisa, regaliz, jengibre
<u>Answer:</u>
A mating of two people of medium height (where three genes control height): AaBbCc x AaBbCc produce <u>Seven</u> distinct phenotypes determined by the number of genes inherited.
Option: (D)
<u>Explanation:</u>
- Traits are the characters that we observe. When the parents AaBbCc and AaBbCc are crossed then AABBCC and aabbcc are two different dominant and recessive genomes seen in the offspring.
- Offspring with AABBCC will be height whereas aabbcc will be dwarf. There will be offspring with different heights depending upon the dominant and recessive gene present in them.
- Another genome produced are AABBCc/AaBBCC/AABbCC, next will have four dominant and 2 recessive, next will have 3 dominant and 3 recessive AaBbCc, next will have 2 dominant and 4 recessive, one dominant and five recessive. All together offspring produced will be 64
The phenotype is just a characteristic/trait.
For instance Brown and Green are phenotypes of eye color.
This can also be used in Punnet Squares, and could be displayed as B and G.
B equaling dominant Brown, and G = dominant Green, vice versa to g and b where they are recessive.
