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Dmitrij [34]
3 years ago
13

Simplify: 9y(-3y to the eighth power)

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
-27y^4 (^=exponent) so -27y to the fourth power. Hope this helps!
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Susan made the following 3-dimensional figure from a net. What 2-dimensional shapes are used to make the faces of the figure?
konstantin123 [22]

Answer:

D)

Step-by-step explanation:

I don't know if there was a picture, but d will made a triangular prism. All are possible but they will look more like a dome.

5 0
3 years ago
Solve the simultaneous equation 2p - 3q = 4, 3p + 2q = 9. <br>b. if 223= 87 find x<br>​
wolverine [178]

Answer:

Step-by-step explanation:

Given the simultaneous equation 2p - 3q = 4 and 3p + 2q = 9, to get the value of p and q we will use elimination method.

2p - 3q = 4 ...................... 1 * 3

3p + 2q = 9 ..................... 2 * 2

Multiplying equation 1 by 3 and 3 by 2:

6p - 9q = 12

6p + 4q = 18

Subtracting both equation

-9q-4q = 12-18

-13q = -6

q = -6/-13

q = 6/13

Substituting q = 6/13 into equation 2

2p - 3(6/13) = 4

2p - 18/13 = 4

2p = 4+18/13

2p = (52+18)/13

2p = 70/13

p = 70/26

p = 35/13

<em>Hence p = 35/13 and q = 6/13</em>

<em></em>

<em>b) </em>If if 223ₓ = 87 find x

Using the number base system and converting 223ₓ  to base 2 will give us;

223ₓ = 2*x² + 2*x¹ + 3*x⁰

223ₓ  = 2x²+2x+3

​

Substituting back into the equation, 2x²+2x+3 = 87

2x²+2x+3-87 = 0

2x²+2x-84 = 0

x²+x-42 = 0

On factorizing:

(x²+6x)-(7x-42) = 0

x(x+6)-7(x+6) = 0

(x+6)(x-7) = 0

x+6 = 0 and x-7 = 0

x = -6 and 7

<em>Hence the value of x is 7 (neglecting the negative value)</em>

5 0
3 years ago
A batter hits a baseball into the air
azamat

The answer is h(5) = 75.

Where x=5, y=75

4 0
3 years ago
Read 2 more answers
What is the x-intercept for the equation? 3x + 6y = 24<br> -4<br> 4.<br> 8<br> -8
lesantik [10]

Answer:8

Step-by-step explanation: plug in 0 for y then solve

8 0
3 years ago
The equation of a circle is given below.
BARSIC [14]

<u>Given</u>:

The equation of the circle is x^2+(y+4)^2=64

We need to determine the center and radius of the circle.

<u>Center</u>:

The general form of the equation of the circle is (x-h)^2+(y-k)^2=r^2

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation x^2+(y+4)^2=64 to determine the center.

The given equation can be written as,

(x-0)^2+(y+4)^2=64

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

<u>Radius:</u>

Let us compare the general form of the equation of the circle with the given equation x^2+(y+4)^2=64 to determine the radius.

Hence, the given equation can be written as,

x^2+(y+4)^2=8^2

Comparing the two equation, we get;

r^2=8^2

 r=8

Thus, the radius of the circle is 8

3 0
3 years ago
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