Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).
TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.
Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,
PQ^2 + QR^2 = PR^2
PQ^2 + 5^2 = 9^2
PQ^2 = 56
PQ = √56 = 2√14
Then the perimeter of PQRS is
PQ + QR + RS + SP = 2√14 + 5 + 5 + 2√14 = 10 + 4√14
and so the answer is B.
( 6 − 7 i ) ( − 8 + 3 i )
First FOIL:
( 6 − 7 i ) ( − 8 + 3 i ) = -48 + 18i + 56i -21i^2
Combine like terms
= -48 + 74i -21i^2
Convert i^2 = -1
= -48 + 74i -21(-1)
And simplify
= -48 + 74i + 21
= -27 + 74i
Answer:
7x + 6 = - 48
Step-by-step explanation:
Given
x + 
= - 6
Multiply through by 8 ( the LCM of 8 and 4 ) to clear the fractions
7x + 6 = - 48 ← same equation without fractions
Formula for Perimeter of Rectangle:
P = 2(L + W)
Plug in 160:
160 = 2(L + W)
L = 4W
<span>So we can plug in '4W' for 'L' in the first equation.</span>
<span>160 = 2(L + W)
160 = 2(4W + W)
Combine like terms:
160 = 2(5W)
160 = 10W
Divide 10 to both sides:
W = 16
Now we can plug this back into any of the two equations to find the length.
L = 4W
L = 4(16)
L = 64
So the width is 16, and the length is 64.</span>
