Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi. (4 points)

A dairy needs 365 gallons of milk containing 7% butterfat. How many gallons each of milk containing 9% butterfat and milk contai

azamat

The amount in gallons of each milk containing 9% butterfat and milk containing 4% butterfat which must be used to obtain the desired 365 gallons are;

219 gallons of 9% fat.
146 gallons of 7% fat.

<h3>What quantity of each type of milk is required for the desired 365 gallon?</h3>

It follows from the task content that the quantity of each type of milk required to arrive at the targeted fat content and quantity of milk are to be determined.

Let x = quantity of 9% fat milk and

Let y = quantity of 4% fat milk

Therefore, by mass balance; we have;

x + y = 365.

Where; y = 365 - x.

Also, by fat balance; we have;

(9% × x) + (4% × y) = (7% × 365)

9x + 4y = 2555

Therefore, the two equations to be solved simultaneously by substituting y from the first equation into the second equation as follows;

9x + 4 (365 - x) = 2555

5x = 1095

x = 1095/5

x = 219 gallons.

Also, y = 365 - 219 = 146 gallons.

Read more on simultaneous equations;

brainly.com/question/16863577

#SPJ1

6 0

1 year ago

Someone please help:)

Georgia [21]

I guess it's the first dia. which is not intersecting....

3 0

3 years ago

Marc was born on his grandmother’s 56th birthday. In how many years will Marcs grandmother be 5 times as Marc will be then?

sergey [27]

Answer:

<u>In 14 years Marc's grandmother will be 5 times as Marc will be then</u>

Step-by-step explanation:

1. Information given to us to solve the problem:

Marc's age today = 0

Marc's grandmother age today = 56

2. In how many years will Marc's grandmother be 5 times as Marc will be then?

x = Number of years when Marc's grandmother age will be 5 times as Marc will be then

Let's solve for x, this way:

5 times Marc age in x years = Marc's grandmother age in x years

5 (0 + x) = 56 + x

5x = 56 + x

5x - x = 56 (Subtracting x at both sides)

4x = 56

x = 56/4

Let's prove that x = 14 is correct:

5 (0 + 14) = 56 + 14

70 = 70

We proved that x = 14 is correct

<u>In 14 years Marc's grandmother will be 5 times as Marc will be then</u>

6 0

3 years ago

Wanda's homework was to find 73% of $400 A tape diagram. 0 dollars is 0 percent. Question mark dollars is 73 percent. 400 dollar

Harrizon [31]

Answer: C

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In a large section of a statistics class, the points for the final exam are normally distributed, with a mean of 71 and a stan

kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that $\mu = 71, \sigma = 7$

Grades are assigned such that the top 10% receive A's, the next 20% received B's, the middle 40% receive C's, the next 20% receive D's, and the bottom 10% receive F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 71}{7}$