Answer:
see explanation
Step-by-step explanation:
Given
cotθ = =
Use Pythagoras' identity to calculate the hypotenuse h
h² = 4² + 5² = 16 + 25 = 41 ( take square root of both sides )
h =
θ is in quadrant III where sinθ < 0 and secθ < 0
sinθ = = - = -
cosθ = = -
secθ = = -
Answer:
f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Step-by-step explanation:
f' of tan(x) = sec²(x)
f' of csc(x) = -csc(x)cot(x)
General Power Rule: uⁿ = xuⁿ⁻¹ · u'
Step 1: Write equation
2tan³(x) + 5csc⁴(x)
Step 2: Rewrite
2(tan(x))³ + 5(csc(x))⁴
Step 3: Find derivative
d/dx 2(tan(x))³ + 5(csc(x))⁴
- General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
- Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
- Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
- Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Answer:
428÷6=5=7×8+9÷{6}r6×7×8÷8=8%8+8×
Answer:
C. 0.10, because 6 of the 60 days were clear
Step-by-step explanation:
As per the question, you're in San Antonio which indicates 1st look in San Antonio's row.
Then we want the chance or probability it's clear, so look in clear column. We will find the value that is "6"
So 6 on a total of 60 which is the huge total. Accordingly, Probability it is right, since that you are into the San Antonio. Then it becomes
= 0.1
Therefore the right answer is C.
Answer:
yes its linear
Step-by-step explanation:
bc