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Rama09 [41]
3 years ago
9

On an average day a horse might drink 50l a sheep might drink 4l and a chicken might drink 200ml. How much water would a farm wi

th 3 horses 15 sheep and 12 chickens need for a day
Mathematics
1 answer:
aksik [14]3 years ago
3 0
50 L X 3 = 150 L (water value for horses)
4 L X 15 = 60 L (water value for sheep)
200 mL X 12 = 2,400 mL or 2.4 L (water value for chickens)
Add them all together.
150 + 60 + 2.4 = 212.4 L of water is used daily
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Answer:

67.3°C

Step-by-step explanation:

A = 25, T(0) = 100, T(1) = 90, find T(4)

dT/dt = -k(T - A)

d(T - A)/dt = -k(T - A)

d(T - A)/(T - A) = -k dt

ln(T - A) = lnC - kt

T(t) -A=Ce^{-kt}\\T(t) = A + Ce^{-kt} = 25 + Ce^{-kt}\\T(0) = 25 + C = 100\\C=75

T(t) = 25 + 75e^{-kt}\\T(1) = 25 + 75e^{-k} = 90\\75e^{-k} = 65\\e^{-k} = \frac{65}{75}, k = ln\frac{75}{65} = 0.1431\\T(t) = 25+75e^{-0.1431t}\\T(4) = 25+75e^{-0.1431\times4} = 67.3

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2 years ago
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Step-by-step explanation:

8 0
2 years ago
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Ludmilka [50]
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