Kinetic Energy
=
1
2
m
v
2
=
1
2
1120
⋅
40
2
=
896000
J
=
8.96
⋅
10
5
J
Hello!
Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.
A) x-axis, y=x, y-axis, x-axis
b) x-axis, y-axis, x-axis
c) y=x, x-axis, x-axis
d) y-axis, x-axis, y-axis, x-axis
The best answer is C180 rotation wud take that point to 4th quadrant
reflection in x-axis takes that to 1st quadrant
<span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started
</span>
Hope this Helps! :)
Answer:
3rd option: 60 degrees
Step-by-step explanation:
We can see in the diagram that the angle on C is a supplementary angle, which means that the sum of 135 and internal angle will be equal to 180 degrees.
Let x be the internal angle,
Then
x+135 = 180
x = 180-135
x = 45 degrees
So now we know that two interior angles of the triangle.
Also we know that sum of all internal angles of triangle is 180 degrees.
Using the same postulate:
A+B+C = 180
75 + B + 45 = 180
120+B = 180
B = 180 - 120
B = 60 degrees
So,
third option is the correct answer ..
To do these, start by looking at the "b" value -6.
divide it by 2
-6/2 = -3
now square this number
(-3)^2 = 9
this is what you need for the "c" value
there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)
y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4
vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.
