Step-by-step explanation:
![\frac{48}{2x + 7} = \frac{40}{5x - 2} \\ 48(5x - 2) = 40(2x + 7) \\ 240x - 96 = 80x + 280 \\ 240x - 80x = 96 + 280 \\ 160x = 376 \\ \frac{160x}{160} = \frac{376}{160} \\ x = 2.35](https://tex.z-dn.net/?f=%20%5Cfrac%7B48%7D%7B2x%20%2B%207%7D%20%20%3D%20%20%5Cfrac%7B40%7D%7B5x%20-%202%7D%20%20%5C%5C%2048%285x%20-%202%29%20%3D%2040%282x%20%2B%207%29%20%5C%5C%20240x%20-%2096%20%3D%2080x%20%2B%20280%20%5C%5C%20240x%20-%2080x%20%3D%2096%20%2B%20280%20%5C%5C%20160x%20%3D%20376%20%5C%5C%20%20%5Cfrac%7B160x%7D%7B160%7D%20%20%3D%20%20%5Cfrac%7B376%7D%7B160%7D%20%20%5C%5C%20x%20%3D%202.35)
9514 1404 393
Answer:
te, tm, (m-e), t
Step-by-step explanation:
The problem statement tells you how to interpret the expressions and their parts.
Swap the top two expressions on the right and the list will be in the appropriate order:
Answer:
cot(∅) = ![\frac{10\sqrt{15} }{15}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5Csqrt%7B15%7D%20%7D%7B15%7D)
Step-by-step explanation:
tan ∅ and cot ∅ are inverse functions
therefore the inverse of
tan ∅ = √15 / 10
is equal to
cot ∅ = 10 / √15
Rationalizing the denominator
* ![\frac{\sqrt{15} }{\sqrt{15} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B15%7D%20%7D%7B%5Csqrt%7B15%7D%20%7D)
cot ∅ = ![\frac{10\sqrt{15} }{15}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5Csqrt%7B15%7D%20%7D%7B15%7D)
Answer:
The answer to your question is: x + 1 residue -3
Step-by-step explanation:
We can use synthetic division
x² - 4 / x - 1
1 0 -4 1
1 1
1 1 -3
Result
x + 1 residue -3
Use distrubutive property <em>a(b + c) = ab + ac</em>
6(5r - 4) - 2(r - 7s - 3)
= (6)(5r) + (6)(-4) + (-2)(r) + (-2)(-7s) + (-2)(-3)
= 30r - 24 - 2r + 14s + 6
= (30r - 2r) + 14s + (-24 + 6)
<h3>= 28r + 14s - 18</h3>