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Zarrin [17]
4 years ago
14

What is 70/7 as a mixed number

Mathematics
2 answers:
Julli [10]4 years ago
8 0

Answer:10 THERE IS NO MIXED NUMBER

Step-by-step explanation: 7*10=70 OR 70/7=10

Zigmanuir [339]4 years ago
4 0

Answer: 10

Explanation:

Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

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100 men and 100 women were surveyed and asked what there favorite ice ream flavor was, chart below
ser-zykov [4K]

Answer:

0.535 prefer chocolate and 0.465 prefer vanilla

Step-by-step explanation:

So starting off with chocolate. 200 people were surveyed. So 100 people would be 0.50 (or half or 50%). So 107 people who prefer chocolate would be a bit more than 0.50. 0.535 prefer chocolate.

Going to vanilla, 93 people prefer it. this is LESS than half so it has to be under 0.50. There is only one that is less than 0.50, which is 0.465. Also using addition, this would be the only logical one.

4 0
4 years ago
Find the value of this expression: (7+5)3-3
Ilia_Sergeevich [38]

The answer is 33

Hope this helps

6 0
3 years ago
Read 2 more answers
What is three divided by two thirds?
Serhud [2]

Answer:

4 1/2

Step-by-step explanation:

3÷ 2/3

Copy dot flip

3 * 3/2

Multiply the numerators

3*3 =9

The denominator is 2

Numerator over denominator

9/2

Change to a mixed number

9/2 = 4 1/2

6 0
4 years ago
M 1 = (2x + 28)<br> m 3= (6x + 4)<br> What is m&lt;2<br> Enter your answer in the box.
s2008m [1.1K]

Answer:

m∠2 = 140°

Step-by-step explanation:

m∠1 = m∠3, since they're vertical angles.

Solve for x:

2x+28=6x+4\\24=4x\\6=x

Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.

m∠1 = (2(6) + 28)°

m∠1 = (12 + 28)°

m∠1 = 40°

Now that we know m∠1, we can now solve for m∠2.

m∠1 + m∠2 = 180°

40° + m∠2 = 180°

m∠2 = 140°

3 0
3 years ago
Let n be a prime number. Determine the number of different necklaces that can be made from n beads of k different colors.
max2010maxim [7]

Answer:

n!/k!(n - k)!

Step-by-step explanation:

The number of beads that can be formed from n beads of k different colors are ⁿCₓ = n!/k!(n - k)!

7 0
3 years ago
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