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borishaifa [10]
3 years ago
15

What is the slops that passes through (5,6) and (7,10)

Mathematics
2 answers:
Triss [41]3 years ago
7 0
2 is the correct answer I believe
Alex Ar [27]3 years ago
6 0
The slope is m = 2
hope it helps
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What is 40 3/5 - 3/4
Aleks [24]

Answer:

39.85

Step-by-step explanation:

40 3/5 - 3/4

Find a LCF first:

5*4 = 20

4*5 = 20

The LCF is 20.

40 12/20 - 15/20

812/20 - 15/20

797/20

39.85

4 0
3 years ago
Read 2 more answers
Find the slope of the line through each pair of points
NNADVOKAT [17]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

95)

(-13,\ -10)\to x_1=-13,\ y_1=-10\\(16,\ 16)\to x_2=16,\ y_2=16

substitute:

m=\dfrac{16-(-10)}{16-(-13)}=\dfrac{16+10}{16+13}=\dfrac{26}{29}

96)

(6,\ -16)\to x_1=6,\ y_1=-16\\(-15,\ 9)\to x_2=-15,\ y_2=9

substitute:

m=\dfrac{9-(-16)}{-15-6}=\dfrac{25}{-21}=-\dfrac{25}{21}

97)

(12,\ -11)\to x_1=12,\ y_1=-11\\(14,\ -12)\to x_2=14,\ y_2=-12

substitute:

m=\dfrac{-12-(-11)}{14-12}=\dfrac{-12+11}{2}=-\dfrac{1}{2}

OK. I think you already know how to solve it. I will give short solutions now.

98)

m=\dfrac{15-(-3)}{8-(-14)}=\dfrac{18}{22}=\dfrac{9}{11}

99)

m=\dfrac{3-(-5)}{-7-3}=\dfrac{8}{-10}=-\dfrac{4}{5}

100)

m=\dfrac{-8-8}{-11-0}=\dfrac{-16}{-11}=\dfrac{16}{11}

101)

m=\dfrac{13-(-5)}{-13-(-13)}=\dfrac{18}{0}!!!-\boxed{NOT\ EXIST}

102)

m=\dfrac{18-1}{-10-2}=\dfrac{17}{-12}=-\dfrac{17}{12}

103)

m=\dfrac{19-14}{7-(-17)}=\dfrac{5}{24}

104)

m=\dfrac{12-0}{-6-4}=\dfrac{12}{-10}=-\dfrac{6}{5}

5 0
3 years ago
The sum of a number and six times its reciprocal is 10. Find the number​
Andreas93 [3]

Answer:

two solutions work: x = 5 + \sqrt{19} and x = 5 - \sqrt{19}

Step-by-step explanation:

x + 6 ( 1/x ) = 10

x^2 + 6 = 10x

x^2 - 10x + 6 = 0

x = 5 + \sqrt{19}, 5 - \sqrt{19}

6 0
3 years ago
Which option/bubble is it??
jek_recluse [69]
The option is the 3rd bubble
3 0
3 years ago
You are in charge of planning a reunion party for your high school alumni. The food will cost $12 per person. The rental fee for
castortr0y [4]

Answer:

$3820 total, $32 per alumnus.

Step-by-step explanation:

The total cost will be 12\times120+650+730+1000=3820

Each alumnus pays \frac{3820}{120} =31\frac{5}{6}

Rounding to nearest whole number = $32 per alumnus.

5 0
2 years ago
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