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DochEvi [55]
4 years ago
12

Three side lengths of a right triangle are given. Use the drop-down menus to explain why matters where you substitute the length

s in the Pythagorean Theorem.
In the Pythagorean Theorem, the two shortest sides
must always be substituted for the side lengths, not the hypotenuse.

(Am I correct, if yes, can you explain why)
Mathematics
1 answer:
SVEN [57.7K]4 years ago
5 0

Answer:

The Pythagorean Theorem is used for right triangles only, because it's a mathematical relation between the legs of the triangle and the hypothenuse, where each leg must be less than the length of the hypothenuse.

It's important to correctly identify each element of the triangle, that is, which sides are legs, and which side is the hypothenuse, because the Pythagorean Theorem has a specific order, that means, if we make a mistake identifying each element, then the result will be wrong.

For example, the expression c^{2}=a^{2}  +b^{2} is the theorem, where c is the hypothenuse. This theorem states that the square of the hypothenuse (longest side) is equal to the sum of the square of the legs. So, if we call c a leg instead of the hypothenuse, the theorem won't work.

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In the larger figure, this length is of 2 units, so the dilation has a scale factor of 2 units. The rotation, due to the coordinates changing, is of 90º counterclockwise(if it was across the x-axis, only the y coordinate would change, but on image II, both coordinates change).

So the correct answer is:

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8 0
3 years ago
What is the volume of a right circular cylinder with a radius of 6 m and a height of 9 m?
geniusboy [140]

The volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.

The volume of a substance is the total space occupied by a three-dimensional object.

The volume of a right circular cylinder with a radius of r units and a height of h units is given by the formula <u>V = πr²h square units</u>.

We are asked to find the volume of the right circular cylinder with a radius of 6 m and a height of 9 m.

Substituting these values in the formula, we get Volume,

V = π(6)²(9) m² = 324π m² = 1017.876 m² ≈ 1018 m².

Therefore, the volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.

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