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IgorC [24]
3 years ago
11

It turns out that (0.125)^3 can be written as 2^a for some integer a. Find a.

Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer:

a=-9

Step-by-step explanation:

We begin with (0.125)^3

First, we can convert this decimal into a fraction

(\frac{1}{8} )^3

Now, we can simplify the denominator of the fraction

(\frac{1}{2^{3} } )^3

Next, we can remove the fraction by rewriting the fraction with a negative power.

(2^{-3} )^3

Lastly, we can remove the parenthesis by multiplying the powers together.

2^{-9}

This means that a=-9

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7x+8y=−46 2y − 6=0 What is the solution (x,y) to the system of equations above?
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Answer:

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Step-by-step explanation:

You can do it algebraically (substitution or elimination) or graphically. I will be using substitution to solve this.

Step 1: Rewrite 2nd equation

2y = 6

y = 3

Step 2: Plug in <em>y</em>

7x + 8(3) = -46

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