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vitfil [10]
3 years ago
7

I need help with #6 please help and I need the work

Mathematics
2 answers:
klasskru [66]3 years ago
8 0

So for this, we have to replace p for 700 to solve for how many candy bars it takes to make that profit. Our equation will look like this: 700=1.50n-500

Firstly, add 500 onto both sides of the equation: 1200=1.50n

Next, divide both sides by 1.50, and your answer will be 800=n

In context, in order to make a profit of $700, you must sell 800 candy bars.

Assoli18 [71]3 years ago
7 0

Since p represents profit, and we want to calculate the amount of candy bars to be sold to get a profit of 700 dollars, substitute 700 for p in the equation to calculate the value of n (the number of candy bars that must be sold).

p = 1.5n - 500 (given)

700 = 1.5n - 500 (substitute)

1200 = 1.5n (add 500 to both sides)

800 = n (divide both sides by 1.5)

Answer:

800 candy bars must be sold to make a profit of $700.

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Andreas93 [3]

Hi!

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<em>Hope this helps! Have an amazing day <3</em>

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4 0
3 years ago
lisa sold 81 magazine subscriptions, which is 27% of her class fundraising goal. how many magazine subscriptions does her class
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Game consoles: A poll surveyed 341 video gamers, and 89 of them said that they prefer playing games on a console, rather than a
Orlov [11]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of gamers that prefer consoles is less than 28% as the manufacturer claims.

Of 341 surveyed players, 89 said that they prefer using a console.

The sample resulting sample proportion is p'= 89/341= 0.26

If the company claims is true then p<0.28, this will be the alternative hypothesis of the test.

H₀: p ≥ 0.28

H₁: p < 0.28

α: 0.05

To study the population proportion you have to use the approximation of the standard normal Z= \frac{p'-p}{\sqrt{\frac{p(1-p)}{n} } }≈N(0;1)

Z_{H_0}= \frac{0.26-0.28}{\sqrt{\frac{0.28*0.72}{341} } }= -0.82

This test is one-tailed left, i.e. that you'll reject the null hypothesis to small values of Z, and so is the p-value, you can obtain it looking under the standard normal distribution for the probability of obtaining at most -0.82:

P(Z≤-0.82)= 0.206

Using the p-value approach:

If p-value ≤ α, reject the null hypothesis

If p-value > α, don't reject the null hypothesis

The decision is to not reject the null hypothesis.

Then at a level of 5%, you can conclude that the population proportion of gamers that prefer playing on consoles is at least 28%.

I hope this helps!

4 0
4 years ago
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