Answer:
The average cost of each dinner at Dave's party is <u>$5.79</u>.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.

Two people ordered the $4.95 fish dinner.

Five had the beef dinner at a cost of $6.75.

Total amount of dinner = 
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:


Therefore, the average cost of each dinner at Dave's party is $5.79.
2.27/0.03=75.6 repeating
You put the numbers into a mathematical equation (2.27÷0.03=). You then divide 2.27 by .03. Write the answer as 75.6 repeating.
.67×.3=.201
You first write the numbers into a mathematical equation (.67×.3=). Then you divide .67 by .3. Lastly you write the answer as .201.
You are enough I know this is not what you expect but just know YOU are enough you are awesome and amazing whatever you are going through just know YOU are enough
Nick and Sara age 10.
I think...