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satela [25.4K]
3 years ago
6

What is the decay factor that corresponds to a product that decreases its value first by 20%, and than decreases by 40% of its v

alue, and finally decreases by 62% of its value?
Mathematics
2 answers:
Georgia [21]3 years ago
8 0
(1-0.2)(1-0.4)(1-0.62) = (0.8)(0.6)(0.38) = 0.1824

Answer: 0.1824
Zigmanuir [339]3 years ago
4 0

Answer: The decay factor that corresponds to a product is 18.24%.

Step-by-step explanation:

Since we have given that

Rate  of decrement firstly = 20%

Rate of decrement secondly = 40%

Rate of decrement finally = 62%

As we know that

Decay factor is given by

(1-\dfrac{r_1}{100})(1-\dfrac{r_2}{100})(1-\dfrac{r_3}{100})\\\\=(1-0.20)(1-0.40)(1-0.62)\\\\=0.80\times 0.60\times 0.38\\\\=0.1824\\\\=18.24\%

Hence, the decay factor that corresponds to a product is 18.24%.

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Please help me with this.
xenn [34]

By solving a system of equations, we will see that you must use 6.67 pounds of chocolate-covered almonds.

<h3>How to solve the system of equations?</h3>

First, we need to define the two variables:

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  • y = number of pounds of the $5.99 chocolate-covered raisins used.

If we mix that, we will get:

x*$9.99 + y*$5.99 = (x + y)*C

That equation means that the cost of the individual elements of the mixture, must be equal to the total cost of the mixture. Where C is the cost of each pound of the mixture, and we know that:

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Now we can solve that for x:

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If you want to learn more about systems of equations:

brainly.com/question/13729904

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3 0
2 years ago
g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control
Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that p = \frac{1}{33}

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This is:

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In which

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P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426

0.1426 = 14.26% probability that at least one of the births results in a defect.

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Answer: 17

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