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Lena [83]
3 years ago
13

Each shelf holds 5 hermit-crab cages and 3 hermit-crab care booklets. If there are 23 hermit crab cages and 12 booklets to displ

ay, what would you do first to see how many shelves are needed?
Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

1. Each shelf holds 5 hermit-crab cages. There are 23 hermit crab cages to be displayed. Divide the number of hermit crab cages to be displayed by the number of hermit crab cages that can be displayed on each shelf:

23=5\cdot 4+3.

This means that you need 5 shelves (4 shelves is not enough, because 3 hermit crab cages will be not displayed).

2. Each shelf holds 3 hermit-crab care booklets. There are 12 hermit-crab care booklets to be displayed. Divide the number of hermit-crab care booklets to be displayed by the number of hermit-crab care booklets that can be displayed on each shelf:

12=3\cdot 4.

This means that you need 4 shelves.

Answer: first, you have to divide 23 by 5 and find the quotient and remainder and divide 12 by 3 and find the quotient and remainder. Then you have to determine the number of shelves needed. You need 5 shelves.

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George observes that for every increase of 1 in the value of x, there is a increase of 60 in the corresponding value of y. He cl
Brums [2.3K]

Hi there!

<u><em>FACTS</em></u><em> :</em>

<em>To see if multiple ratios are proportional, you can write them as fractions, reduce them, and compare them. If the reduced fractions are all the same, then you have proportionnal ratios. You can also write them as fractions and divide the numerator (top number) by its denominator (bottom number), and compare the decimal numbers the same way you would compare the fractions (I personnaly find this method easier because you don't need to simplify the fractions).</em>

<u>STEPS TO ANSWER:</u>

x = 1 ; y = 90 → \frac{1}{90} = 1 ÷ 90 = <u>0.01111111...</u>


x = 2 ; y = 150 → \frac{2}{150} = 2 ÷ 150 = <u>0.0133333...</u>


x = 3 ; y = 210 → \frac{3}{210} = 3 ÷ 210 = <u>0.01428571</u>


x = 4 ; y = 270 → \frac{4}{270} = 4 ÷ 270 = <u>0.0148148...</u>


x = 5 ; y = 330 → \frac{5}{330} = 5 ÷ 330 = <u>0.01515152</u>


<em>** You didn't really need to calculate them all because even the first two decimal numbers weren't equivalent, but I wanted to show you the whole process so I calculated them all.</em>


⇒ If you compare all the decimals you got, you can easily see that they are not the same, which means that the ratios between the values of "x" and the values of "y" are not proportional. Therefore, George's reasoning wasn't good.


There you go! I really hope this helped, if there's anything just let me know! :)

5 0
3 years ago
Write an equation in point-slope form of the line that passes through (3, -8) and (7,-2).
sashaice [31]

Answer:

A line that passes through (3, -8) and (7,-2).

Denote equation of that line: y = ax + b

=> Slope a can be directly determined by:

a = (7 - 3)/(-2 - -8) = 4/6 = 2/3

=> y = (2/3)x + b

This line passes (3, -8), then: -8 = (2/3)*3 + b => -8 = 2 + b => b = -10

=> y =(2/3)x - 10

There are other ways to find equation of line.

Hope this helps!

:)

3 0
2 years ago
Read 2 more answers
{[3 x (3+6) - 5] + 20 x 2
Nataliya [291]

Answer:

a. 62

Step-by-step explanation:

use the Bodmas method

=3×9-5+20×2

=<u>62</u><u> </u>

7 0
3 years ago
Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
4 0
3 years ago
Read 2 more answers
The actual distance between two villages is 120 kilometers. On a map of the area, 0.5 centimeter represents 2 kilometers.
stira [4]

Answer:

30 centimeters

Step-by-step explanation:

120 ÷2 =60 now you must use only .5 of that number so you have thirty

3 0
2 years ago
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