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Lena [83]
3 years ago
13

Each shelf holds 5 hermit-crab cages and 3 hermit-crab care booklets. If there are 23 hermit crab cages and 12 booklets to displ

ay, what would you do first to see how many shelves are needed?
Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

1. Each shelf holds 5 hermit-crab cages. There are 23 hermit crab cages to be displayed. Divide the number of hermit crab cages to be displayed by the number of hermit crab cages that can be displayed on each shelf:

23=5\cdot 4+3.

This means that you need 5 shelves (4 shelves is not enough, because 3 hermit crab cages will be not displayed).

2. Each shelf holds 3 hermit-crab care booklets. There are 12 hermit-crab care booklets to be displayed. Divide the number of hermit-crab care booklets to be displayed by the number of hermit-crab care booklets that can be displayed on each shelf:

12=3\cdot 4.

This means that you need 4 shelves.

Answer: first, you have to divide 23 by 5 and find the quotient and remainder and divide 12 by 3 and find the quotient and remainder. Then you have to determine the number of shelves needed. You need 5 shelves.

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Sixty-five percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sele
Serhud [2]

Answer:

The outcomes of this binomial distribution that would be considered unusual is {0, 1, 2, 8}.

Step-by-step explanation:

The outcomes provided are:

(A) 0, 1, 2, 6, 7, 8

(B) 0, 1, 2, 7, 8

(C) 0, 1, 7, 8

(D) 0, 1, 2, 8

Solution:

The random variable <em>X</em> can be defined as the number of employees who judge their co-workers by cleanliness.

The probability of <em>X</em> is:

P (X) = 0.65

The number of employees selected is:

<em>n</em> = 8

An unusual outcome, in probability theory, has a probability of occurrence less than or equal to 0.05.

Since outcomes 0 and 1 are contained in all the options, we will check for <em>X</em> = 2.

Compute the value of P (X = 2) as follows:

P(X=2)={8\choose 2}(0.65)^{2}(0.35)^{8-2}

                =28\times 0.4225\times 0.001838265625\\=0.02175\\\approx 0.022

So <em>X</em> = 2 is unusual.

Similarly check for X = 6, 7 and 8.

P (X = 6) = 0.2587 > 0.05

X = 6 not unusual

P (X = 7) = 0.1373 > 0.05

X = 7 not unusual

P (X = 8) = 0.0319

X = 8 is unusual.

Thus, the outcomes of this binomial distribution that would be considered unusual is {0, 1, 2, 8}.

3 0
3 years ago
Working together, two pumps can drain a certain pool in 6 hours. If it takes the older pump 15 hours to drain the pool by itself
stellarik [79]

Answer:

10

Step-by-step explanation:

Rate of drainage for pump A and B = [1 pool drained]/[6 hours]

Rate of drainage for pump A (older pump) = [1 pool drained]/[15 hours]

Rate for pump B (newer pump) = [1 pool drained]/[t hours]

Thus, adding the rate of drainage of A and B,

1/t + 1/15 = 1/6

t=10

5 0
3 years ago
Plss help if you I don’t how to find the answer
leonid [27]

answer

11x = 480

i dont know

5 0
2 years ago
What number can be written as 40 plus 5 ?
Sergio [31]
40+5=45 is written in extended form so your answer is 45
5 0
3 years ago
Read 2 more answers
Factor and\or expand the following expression : 3(2x + w)
lutik1710 [3]

Answer:

6x +3w

Step-by-step explanation:

3(2x + w)

Distribute

3*2x +3*w

6x +3w

7 0
3 years ago
Read 2 more answers
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