All categories

3 years ago

Find the perimeter AND area of parallelogram ABCD. SHOW ALL WORK

Mathematics

1 answer:

Firdavs [7]3 years ago

4 0

Answer:

Step-by-step explanation:

use the distance formula to find the lengths of the sides then do bas times height for the area and add the sides together for the perimeter

You might be interested in

frank is 5 years younger than twice the age of his cousin Alonso. Frank is 17 years old. Which equation could be used to determi

monitta

Answer:

Hi there!

Your answer is:

17= 2A-5

Alonzo is 11

Step-by-step explanation:

Frank=2A -5

Frank = 17

17= 2A-5

A = Alonzo's age

Alonzo's age is:

17= 2A-5

22 = 2A

11= A

5 0

3 years ago

In recent years the mean number of miles driven per year by residents of a particular state was 11,568. A researcher wishes to t

aleksandrvk [35]

Answer:

The degrees of freedom are given by:

$df =n-1= 62 -1=61$

And we want to find a critical value on the t distribution with 61 degrees of freedom who accumulates 0.025 of the area on each tail and the critical value would be $t_{\alpha/2}= \pm 2.00$

And the rejection region would be $|t_{calc}| >2.00$

Step-by-step explanation:

Data given and notation

$\bar X=10822$ represent the sample mean

$s=1741$ represent the sample standard deviation

$n=62$ sample size

$\mu_o =11568$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean differs from 11568, the system of hypothesis would be:

Null hypothesis: $\mu =11568$

Alternative hypothesis: $\mu \neq 11568$

The degrees of freedom are given by:

$df =n-1= 62 -1=61$

And we want to find a critical value on the t distribution with 61 degrees of freedom who accumulates 0.025 of the area on each tail and the critical value would be $t_{\alpha/2}= \pm 2.00$

And the rejection region would be $|t_{calc}| >2.00$

8 0

3 years ago

Use the graph below to answer the question that follows:

lys-0071 [83]

D is the answer............................

8 0

3 years ago

Read 2 more answers

A cereal manufacturer is concerned that the boxes of cereal not be under filled or overfilled. Each box of cereal is supposed to

Vaselesa [24]

Answer:

We conclude that the population average weight of a cereal box is equal to 13 ounces.

Step-by-step explanation:

We are given that a cereal manufacturer is concerned that the boxes of cereal not be under filled or overfilled.

A random sample of 36 boxes is tested. The sample average weight is 12.85 ounces and the sample standard deviation is 0.75 ounces.

Let $\mu$ = population average weight of a cereal box

So, Null Hypothesis, $H_0$ : $\mu$ = 13 ounces {means that the population average weight of a cereal box is equal to 13 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 13 ounces {means that the population average weight of a cereal box differs from 13 ounces}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average weight = 12.85 ounces

$\sigma$ = sample standard deviation = 0.75 ounces

n = sample of boxes = 36

So, test statistics = $\frac{12.85-13}{\frac{0.75}{\sqrt{36} } }$ ~ $t_3_5$

= -1.20

The value of the test statistics is -1.20.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the t table gives critical values between -2.03 and 2.03 at 35 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population average weight of a cereal box is equal to 13 ounces.

3 0

3 years ago

The Rockwell hardness of a metal is determined by impressing a hardened point into the surface of the metal and then measuring t

gayaneshka [121]

Answer:

Answer for the question:

The Rockwell hardness of a metal is determined by impressing a hardened point into the surface of the metal and then measuring the depth of penetration of the point. Suppose the Rockwell hardness of a particular alloy is normally distributed with mean 69 and standard deviation 2.7.

a. If a specimen is acceptable only if its hardness is between 67 and 75, what is the probability that a randomly chosen specimen has an acceptable hardness?

b. If the acceptable range of hardness is (69-C, 69+C), for what value of C would 95% of all specimens have acceptable hardness?

c. If the acceptable range is as in part (a) and the hardness of each of ten randomly selected specimens is independently determined, what is the expected number of acceptable specimens among the ten?

d. What is the probability that at most eight of ten independently selected specimens have a hardness of less than 72.84(HINT Y=number among the ten specimens with hardness less than72.84 is a binomial variable; what is p?)

is given in the attachment.

Step-by-step explanation:

Download pdf

7 0

3 years ago