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bogdanovich [222]
3 years ago
14

a. At the beginning of the year, Addison Company’s assets are $300,000 and its equity is $100,000. During the year, assets incre

ase $80,000 and liabilities increase $50,000. What is the equity at year-end?
Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Equity at the end of the year = $130,000

Step-by-step explanation:

Step 1:

Given ,

Asset of the company at beginning of year = $300,000

Equity  of the company at beginning of year = $100,000

Increase of the assets  during the year = $80,000

Increase of the liabilities  during the year =  $50,000

We need to find the equity at the year end.

Step 2 :

The equity at any point can be obtained by using the formula

equity = assets - liability

At the beginning of the year ,

100,000 = 300,000 - liability

So liability = 300,000 - 100,000 = 200,000

Step 3 :

During the year, assets increase $80,000 and liabilities increase $50,000

So assets at the year end = 300,000 + 80,000 = $380,000

liabilities at the year end = 200,000 + 50,000 = $250,000

Therefore

Equity at the year end = 380,000 - 250,000 = $130,000

Step 4 :

Answer :

Equity at the year end = $130,000

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My divisor is 4/7 and my quotient is 7/24. what is the dividend
kompoz [17]

Answer:

1/6.

Step-by-step explanation:

x / 4/7 = 7/24  where x is the dividend.

7x/4  = 7/24

Cross multiply:

7x * 24 =  4*7

x = 28/(7*24)

= 28/168

= 1/6.

3 0
3 years ago
1. Ana was washing dishes at the end of her shift at a restaurant. She washed 30 plates from 7:30 to 7:35. When she finishes was
frutty [35]
She washed 30 plates from 7:30 to 7:35.....so she washed 30 plates in 5 minutes.....30/5 = 6 plates per minute

so if she started washing plates at 7:15 and ended at 7:38...how many plates did she wash....
from 7:15 to 7:38 is 23 minutes...and if she can wash 6 plates per minute, then in 23 minutes, she can wash (23 * 6) = 138 plates <==

the equation...
y = -6x + b...with b being the number of plates she started with and x being the number of minutes and y being the plates she has left to wash...I am not 100% sure on this equation...I am so sorry


4 0
3 years ago
HELP FOR POINTSS
brilliants [131]
The answer would be
C = 10
P = 20
3 0
3 years ago
Read 2 more answers
find the area of field in a form of trapezium whose parallel sides are 10 and 12 and perpendicular distance between them is 6 me
IRISSAK [1]

Answer:

66 m²

Step-by-step explanation:

A = ½ (a + b) h

A = ½ (10 + 12) (6)

A = 66

The area is 66 m².

7 0
3 years ago
On the first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75. The school took in $6
denis-greek [22]

<u>ANSWER:</u>

The price of senior citizen ticket is $4 and price of child ticket is $7.

<u>SOLUTION: </u>

Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.  

The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.  

We need to find what is the price each of one senior citizen tickets and one child tickets.

Let, the price of senior citizen ticket be "x" and price of child ticket be "y"

Then according to the given information,

3x + 9y = 75

x + 3y = 25  [by cancelling the common term 3.

x = 25 – 3y ---- (1)

And, 8x + 5y = 67 ---- (2)

Substitute (1) in (2)

8(25 – 3y) + 5y = 67

200 – 24y + 5y = 67

5y – 24y = 67 – 200

-19y = -133

y = \frac{133}{19}

y = 7

Now substitute y value in (1)

x = 25 – 3(7)

x = 25 – 21  = 4

Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.

4 0
3 years ago
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