ANSWER
The vertex of the graph of

is

EXPLANATION
The vertex form of a parabola is given by

where

is the vertex of the parabola.
The function given to us is

This is already in the vertex form.
When we compare this to the general vertex form, we have,


and

Therefore the vertex of the parabola is

Hence the correct answer is option A.
6/42 in simplest form :
Divide both the nominator and the denominator by the HCF (highest common factor) : 6
6/42 = 6:6/42:6 = 1/7
Given equation is

The given equation is in the form of

a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
Answer:
its 17degree as it is supplement to 163