Solve for b. d = 3a + 3b A. b=d−3a B. b=3a−d/3 C. b=d−3a/a D. b=d−3a/3
1 answer:
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Answer:
Per hour decay of the isotope is 0.96%.
Step-by-step explanation:
Amount of radioactive element remaining after t hours is represented by
where a = initial amount
t = duration of decay (in hours)
Amount remaining after 1 hour will be,
y = 0.9904a
So amount of decay in one hour = a - 0.9904a
= 0.0096a gms
Percentage decay every hour =
=
= 0.958 %
≈ 0.96 %
Therefore, per hour decay of the radioactive isotope is 0.96%.