3 years ago

Solve for b. d = 3a + 3b A. b=d−3a B. b=3a−d/3 C. b=d−3a/a D. b=d−3a/3

1 answer:

Luda [366]3 years ago

3 0

The correct answer here is d

d = 3a + 3b

d - 3a = 3b

d - 3a/3 = b

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