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Mekhanik [1.2K]
3 years ago
7

Solve for b. d = 3a + 3b A. b=d−3a B. b=3a−d/3 C. b=d−3a/a D. b=d−3a/3

Mathematics
1 answer:
Luda [366]3 years ago
3 0

<u><em>The correct answer here is d</em></u>

d = 3a + 3b

d - 3a = 3b

d - 3a/3 = b

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tankabanditka [31]
X=2 my friend 
hope this helps!
8 0
3 years ago
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What is the height of this triangle? Round your answer to the nearest tenth.
love history [14]

Answer:

5.7

Step-by-step explanation:

pythagorean theorem

A^2 + B^2 = C^2

sub in

A^2 + 7^2 = 9^2

simplify

A^2 + 49 = 81

solve

A^2 = 32

solve further

A = \sqrt{32

use calculator and get:

5.65685

round and get:

<u>5.7</u>

5 0
3 years ago
Please help me out!!!!!
Gnoma [55]
Valid because 3 x 3 is 9 :))
3 0
2 years ago
The height, h, in feet of a ball above the ground is given by h = −16t2 + 64t + 80, where t is the time in seconds. How long doe
Gwar [14]

Answer:

t = 5 seconds

Step-by-step explanation:

It is given that, the height h, in feet of a ball above the ground is given by :

h=-16t^2+64t+80

Where t is in seconds

We need to find how long does it take the ball to hit the ground? When it hits the ground, its height will be equal to 0. So,

-16t^2+64t+80=0\\\\t=\dfrac{-64\pm \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=\dfrac{-64+ \sqrt{(64)^2-4\times (-16)(80)} }{2\times -16},\dfrac{-64-\sqrt{(64)^2-4\times (-16)(80)} }{2\times -16}\\\\t=-1\ s\ \text{and}\ t=5\ s

Neglecting negative time.

It means ball will take 5 seconds to hit the ground.

3 0
2 years ago
Find the value of each variable
aniked [119]

Answer:

Answer d)

a= 10*\sqrt{3} b=5*\sqrt{3}, c=15, and d=5

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}

where we use the fact that the sine of 60 degrees can be written as: \frac{\sqrt{3} }{2}

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

d=10*cos(60^o)=10* \frac{1}{2} = 5

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}

where we used the value of the sine function of 30 degrees as one half: \frac{1}{2}

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15

Therefore, our answer agrees with the values shown in option d)

6 0
2 years ago
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