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SpyIntel [72]
3 years ago
13

Hurry fasttt fastttt

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0
The first option I believe thank me plz
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(x^2+3x-7)(2x-5) write in standard form
Gnoma [55]
Hi there!
The question is asking us to simplify the expression (x² + 3x - 7)(2x - 5) and write the answer in standard form. Here is how you do that - 
Original: (x² + 3x - 7)(2x - 5)
Break it apart - [(x² + 3x - 7)(2x)] + [(x² + 3x - 7)(-5)]
Simplify - 
2x³ + 6x² - 14x - 5x² - 15x + 35
Now, combine like terms - 
2x³ + x² - 29x + 35
Therefore, the answer to your query is 2x³ + x² - 29x + 35. Hope this helps!
7 0
3 years ago
henry had charged 847 dollars to his credit card. the cost of his next purchase caused him to exceed his credit limit of 1000
Pachacha [2.7K]

Answer:

The purchase is greater than $153

Step-by-step explanation:

7 0
2 years ago
Help with matrice equations
Tasya [4]

Answer:

21) x=1, y=-1, z=2 and 23) x=3, y=-1, z=-1

Step-by-step explanation:

there are 3 equations in 21)

1) x+y-z=-2

2)2x-y+z=5

3)-x+2y+2z=1

solve for x by adding equation 2) and 1)

2)2x-y+z=5 +  1) x+y-z=-2   = 3x=3, then divide by 3 and x=1

solve for z by adding equation 1) and 3)

1) x+y-z=-2 + 3)-x+2y+2z=1

we then get a new equation, 4), by isolating z

3y+z=-1 which is 4) z=-1-3y

substitute our new equation, 4) z=-1-3y, and x=1 into equation 1) to get y

(1)+y- (-1-3y)=-2

isolate y to get y=-1

then substitute y=-1 into equation 4) to get z=2

check by substituting x=1, y=-1, and z=2 into all 3 equations

there are 3 equations

1)x+3y=0

2)x+y+z=1

3)3x-y-z=11

add equation 3) and 2) together to get x

3)3x-y-z=11 + 2)x+y+z=1

4x=12, x=3

substitute x=3 into equation 1) (3)+ 3y=0 to get y

3y=-3, y=-1

substitute x=3 and y=-1 into equation 2) to get z

(3)+(-1)+z=1,  z=-1

4 0
3 years ago
Question 3 (2 points)
Sveta_85 [38]
I believe the answer is a
5 0
3 years ago
OeowowowkwiHELP ASaPieisowowiiwiwiwiiwiwisnsnsnxxj
puteri [66]

Answer:

5

Step-by-step explanation:

40÷[20-4*(7-4)]

Start with the inner most parentheses

40÷[20-4*(3)]

Then the brackets, multiply first

40÷[20-12]

Then subtract

40÷[8]

We are now left with the division

5

6 0
3 years ago
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