<img src="https://tex.z-dn.net/?f=-r%2B%283r%5E%7B2%7D%2B1%29r%3D4" id="TexFormula1" title="-r+(3r^{2}+1)r=4" alt="-r+(3r^{2}+1)

Dimas [21]

3 years ago

r=4" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

NARA [144]3 years ago

5 0

Answer:

$r = \sqrt[3]{\frac{4}{3} }$

Step-by-step explanation:

$-r + (3r^2 + 1)r = 4\\-r + 3r^3 + r = 4\\3r^3 = 4\\r^3 = \frac{4}{3} \\\\r = \sqrt[3]{\frac{4}{3} }$

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