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allochka39001 [22]
3 years ago
13

Helllp Simplify completely 6x4+9x2+12x/3x

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

Answer:

The answer will be C

If u want just slove and see

You might be interested in
Do not answer if you are unsure.
pishuonlain [190]

Answer:

D. 5

Step-by-step explanation:

Mean: (50+60)/2

110/2

55

Margin of error:

60 - 55

5

3 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Finish multiplying<br> 10/3 ⋅11/12?
Mazyrski [523]
When multiplying fractions, just multiply straight across

10 x 11 = 110
3 x 12 = 36

110/36 is your answer

3 1/18 is simplified mixed fraction


hope this helps
5 0
3 years ago
Read 2 more answers
Anyone good with algebra 2??
sweet [91]
A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.

Let's look at your function.

f(x) = \dfrac{x^2 - 16}{6x - 24}

x^2 - 16  is in the numerator. It is defined for every value of x. There is no problem there.

6x - 24  is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.

We set it equal to zero and solve the equation for x.

6x - 24 = 0

6x = 24

x = 4

For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).

The answer is:

x \ne 4

6 0
3 years ago
Sales fall from 300 per week to 270 per week what’s the percentage change
weeeeeb [17]
Hi there! 

Your question: 

Sales fall from 300 per week to 270 per week what's the percentage change?

My answer:

The formula for calculating percent change is as follows: 

[(y2 - y1)/y1]*100=your percent change 

y2= first value 
y1=second value 

Plug the numbers in: 

[(300-270)/300]*100

[30/300]*100

0.1*100

10 

Therefore, the percent change is 10%

Hope this helps! Let me know if it's incorrect so I can fix it:)
8 0
3 years ago
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