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scoundrel [369]
3 years ago
5

Is a hexagon quadrilateral

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

No. A hexagon is not a quadrilateral.

Step-by-step explanation:

A hexagon has 6 sides, a quadrilateral has 4. :)

notka56 [123]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:Because it has 6 sides

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Use the relationship between the sine and cosine functions to fill in each blank .
rjkz [21]

Answer:

sin(12°)

Step-by-step explanation:

Because sine and cosine are cofunctions, we can use the relation sin(90° - θ) = cosθ to show that cos(78°) = sin(90° - 78°) = sin(12°)

8 0
3 years ago
Convert the following fractions to decimals. 1/8 1/9 2/3 4/7 3/10 5/3 9/5 5/6
il63 [147K]

Answer:

1/8 = 0.125

1/9 = 0.1

2/3 = 0.6

4/7 = 0. 571428

3/10 = 0.3

5/3 = 1.6

9/5 = 1.8

5/6 = 0.83

8 0
3 years ago
3x - 2y &gt; 12<br> Please I need as soon as possible
Novosadov [1.4K]

Answer:

y<-6+3x/2

Step-by-step explanation:

6 0
2 years ago
Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the large
Mandarinka [93]

Let consecutive odd numbers be  

x , x+2 , x+4

Smallest number =x

Middle number =x+2

Largest number =x+4

According to condition (x) +(x+2) -27 = 3(x+4)

                                      x+x+2-27= 3(x+4)

                                      2x-25= 3x+12

Subtracting 2x and 12 both sides

                                   2x-25-2x-12=3x+12-2x-12

                                     -37= x   this is smallest odd number.

Other two odd numbers are (x+2)= (-37+2)=(-35)

                             &                (x+4)=(-37+4)=(-33)

so three consecutive odd numbers are -37 ,-35 , -33


8 0
3 years ago
Determine the maximum value of the objective function, P.
Ad libitum [116K]

Answer:

Maximum (250,125) Answer

Step-by-step explanation:

This is more of a graphing problem than it is anything else.

Begin by graphing all 4 given equations.

When you do that, mark the intersection points of at least 2 lines. In this case it is exactly 2 lines for each intersecting point.

6x + 4y <= 2000 and 2x + 4y <= 1000 intersect at (250,125)

x=>0 and y=>0 intersect at (0,0)

6x + 4y <=2000 and x => 0 intersect at 333.333

2x + 4y <=1000 and y>=0 intersect at  0,250.

Any other intersection points fall outside the range of the givens. The shaded part we are interested in is sort of a very dark green/blue. It is the interior of the quadrilateral determined by the 4 vertices that are marked.

Now all you have to do is determine the maximum point using P=15x + 12y

For 0,0                 P = 15*0 + 12,0 = 0

For 0,250            P = 15*0 + 12*250 = 3000

For 333.3333,0   P = 15*333.3333 + 12*0 = 5000 rounded.

For 250,125        P = 15*250 + 12*125 = 5250  Which is the maximum

Answer (250,125) produces the maximum value Answer

5 0
3 years ago
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