Perimeter = 2(width+length) =28
Let x=width of base, then length of base = (28/2)-x = 14-x
Volume of box = length*width*height
=x(14-x)*5 = 5x(14-x)
Hey there! I'm happy to help!
We know that the perimeter is 2L+2W. Le'ts plug in the values 3 and 5 from our ratio and see what our perimeter would be with that.
2(3)+2(5)
6+10
16
How can we get this 16 to 64?
64/16=4
So, we need to multiply this length and width by four to get 64 as our perimeter!
3*4=12
5*4=20
We can plug this into our perimeter equation
2(12)+2(20)
24+40
64
Therefore, our length is 12 and our width is 20.
Have a wonderful day! :D
The equation for area of a triangle is 0.5*base*height, so when you halve both the base and height, the area gets divided by 4.
The area of the first triangle is 0.5*80*40 = 1600 cm^2.
6 1/4 cm^2 is the same as 25/4 cm^2.
Now, we have to see how many times 1600 cm^2 can be divided by 4 to get 25/4 cm^2.
Area of second triangle: 1600/4 = 400
Area of third triangle: 400/4 = 100
Area of fourth triangle: 100/4 = 25
Area of fifth triangle = 25/4
So, the fifth triangle has an area of 6 1/4 cm^2.
The pattern would be the area of the nth triangle =
Answer:
Option A
Step-by-step explanation:
From the graph attached,
Vertical asymptote of the given function → x = -4
Horizontal asymptote → y = 0
Oblique asymptote → None
Therefore, graph that has been given in the picture is,
F(x) =
Option (A) will be the answer.
if the problem is f(x)=2x-2 domain and range are both positive negative infinity