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const2013 [10]
3 years ago
5

What number is missing from the number pattern? 1,2,5,10,__,26,37​

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

17 is the missing the number

Step-by-step explanation:

Pattern: +1, +3, +5, +7, etc.

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A box is to be constructed with a rectangular base and a height of 5 cm. If the rectangular base must have a perimeter of 28 cm,
maw [93]
Perimeter = 2(width+length) =28
Let x=width of base, then length of base = (28/2)-x = 14-x
Volume of box = length*width*height
=x(14-x)*5 = 5x(14-x)


3 0
3 years ago
Read 2 more answers
The length and width of a rectangle are in a 3:5 ratio. The perimeter of the rectangle is 64. What are the length and width of t
Levart [38]

Hey there! I'm happy to help!

We know that the perimeter is 2L+2W. Le'ts plug in the values 3 and 5 from our ratio and see what our perimeter would be with that.

2(3)+2(5)

6+10

16

How can we get this 16 to 64?

64/16=4

So, we need to multiply this length and width by four to get 64 as our perimeter!

3*4=12

5*4=20

We can plug this into our perimeter equation

2(12)+2(20)

24+40

64

Therefore, our length is 12 and our width is 20.

Have a wonderful day! :D

5 0
3 years ago
Please help me to solve this question
luda_lava [24]
The equation for area of a triangle is 0.5*base*height, so when you halve both the base and height, the area gets divided by 4.

The area of the first triangle is 0.5*80*40 = 1600 cm^2.

6 1/4 cm^2 is the same as 25/4 cm^2.

Now, we have to see how many times 1600 cm^2 can be divided by 4 to get 25/4 cm^2.

Area of second triangle: 1600/4 = 400
Area of third triangle: 400/4 = 100
Area of fourth triangle: 100/4 = 25
Area of fifth triangle = 25/4

So, the fifth triangle has an area of 6 1/4 cm^2.

The pattern would be the area of the nth triangle = \frac{1600}{4^{n-1}}
7 0
3 years ago
Which The following radical functions is graphed below
maks197457 [2]

Answer:

Option A

Step-by-step explanation:

From the graph attached,

Vertical asymptote of the given function → x = -4

Horizontal asymptote → y = 0

Oblique asymptote → None

Therefore, graph that has been given in the picture is,

F(x) = \frac{1}{(x+4)^2}

Option (A) will be the answer.

5 0
3 years ago
What is the domain and range for the following function and its inverse?<br><br> f(x) = x2 – 2
stiks02 [169]

if the problem is f(x)=2x-2 domain and range are both positive negative infinity

8 0
3 years ago
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