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11111nata11111 [884]
3 years ago
8

The cartilage on the ends of long bones serves which of the following functions? *

Biology
1 answer:
boyakko [2]3 years ago
4 0

Answer:

Articular cartilage also serves to cushion the ends of long bones against impact. It does not attach tendons. Red blood cells are made in the bone marrow and the synovial membrane is made of a different type of connective tissue.

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What is Troposphere stratosphere exosphere Mesosphere and Thermosphere
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Earth's atmosphere has a series of layers, each with its own specific traits. Moving upward from ground level, these layers are called the troposphere, stratosphere, mesosphere, thermosphere, and exosphere. The exosphere gradually fades away into the realm of interplanetary space.

Explanation:

Layers of Earth's Atmosphere | Center for Science Educationhttps://scied.ucar.edu

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Explain how a dog meets all of the characteristics of life.
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Please help me out! <br><br> What would an environmentally friendly system look like?
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7 0
3 years ago
Read 2 more answers
A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge
Pie

Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

In mathematical equation, the genotype frequency will be -P²+2Pq+q²=1 and allele frequency will be p+q=1, where p = dominant allele and q will be recessive allele.

In the question, since the observed genotype are-

P² - VV= 16

2Pq- Vv- 92

q²- vv- 12

<u>1. Calculate allele frequency</u>

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele=  124/ 240 = 0.52

P= 0.52

q will be 1-0.52= 0.48

<u>2. Expected genotype frequency</u>

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

2Pq = 2 x 0.52x 0.48 =  0.5

q²= 0.48 x 0.48 =  0.23

<u>3. Expected progeny </u>

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

q²= 0.23 x 120= 28 vv

Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

4 0
3 years ago
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