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Svetradugi [14.3K]
2 years ago
8

Jim’s football team started a play on the 50 yard line. On the first play, the team had a 7-yard gain. On the second play, they

lost 10 yards. What yard line was the ball on at the end of the second play?
Mathematics
2 answers:
wariber [46]2 years ago
6 0

Answer:

47

Step-by-step explanation:

i got it right

lawyer [7]2 years ago
5 0

This is a basic addition/subtraction question. It's saying that they started at the 50 yard line. On the play, they gained 7 yards. So, we'll add 50+7 = 57.

They're at the 57 yard line at this point. On the second play they lost 10 yards (how unfortunate). Thereby, we will subtract 57-10=47.

50 yards +7 yards. -10 yards.

The answer will be that they'll be on the 47 yard line on the next play.

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Simplify the identity: tan cos/sin
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4 0
2 years ago
What does -1 1/6 x 1/4 equal
DIA [1.3K]

The answer would be -7/24

-1x6+1/6x1/4

-6+1/6x1/4

-7/6x1/4

-7x1/6x4

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6 0
2 years ago
find the value of the trigonometric function sin (t) if sec t = -4/3 and the terminal side of angle t lies in quadrant II
kodGreya [7K]

Answer:

sin(t) =\frac{\sqrt{7}}{4}

Step-by-step explanation:

By definition we know that

sec(t) = \frac{1}{cos(t)}

and

cos ^ 2(t) = 1-sin ^ 2(t)

As sec(t) = -\frac{4}{3}

Then

sec(t) = -\frac{4}{3}\\\\\frac{1}{cos(t)} =-\frac{4}{3}\\\\cos(t) = -\frac{3}{4}

Now square both sides of the equation:

cos^2(t) = (-\frac{3}{4})^2

cos^2(t) = \frac{9}{16}\\\\

1-sin^2(t) =\frac{9}{16}\\\\sin^2(t) =1-\frac{9}{16}\\\\sin^2(t) =\frac{7}{16}\\\\sin(t) =\±\sqrt{\frac{7}{16}}

In the second quadrant sin (t) is positive. Then we take the positive root

sin(t) =\sqrt{\frac{7}{16}}

sin(t) =\frac{\sqrt{7}}{4}

8 0
2 years ago
I thought the answer's 102, but it's not, and I'm not sure how to get the correct answer.
MissTica
Hi

I used another place to type my answer because I don't think Brainly has all the tools I need.


I hope this finally help and I am sorry for my laziness :)

As always, I am here to help! 

7 0
2 years ago
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