Answer:

Step-by-step explanation:
Given:
Given point P(6, 6)
The equation of the line.

We need to find the equation of the line perpendicular to the given line that contains P
Solution:
The equation of the line.

Now, we compare the given equation by standard form 
So, slope of the line
, and
y-intercept 
We know that the slope of the perpendicular line 



So, the slope of the perpendicular line
From the above statement, line passes through the point P(6, 6).
Using slope intercept formula to know y-intercept.

Substitute point
and 




So, the y-intercept of the perpendicular line 
Using point slope formula.

Substitute
and
in above equation.

Therefore: the equation of the perpendicular line 
Step-by-step explanation:
<u>Substitute f(0) into the function:</u>

<u>Include exponent:</u>

<u>Multiply:</u>

Answer:
Y=20
Step-by-step explanation:
y equals 20 because you simplify both sides of the equation then you have an isolated variable
Answer:
After the reflection over the line y = -x, the image of the point is: (-3,-2)
Step-by-step explanation:
When a given point is reflected over a line the point only changes place but the distance between the point and the line remains same.
Let (x,y) be a point on the plane
and
y = -x be a line on the plane
When a point is reflected over a line y = -x , the coordinates of the point are exchanged which means x becomes y and y becomes x and both are negated
So (x,y) will become (-y,-x)
Given point is:
(2,3)
After the reflection over the line y = -x, the image of the point is: (-3,-2)