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3 years ago

Which rotation about its center will carry a regular decagon onto itself

Mathematics

2 answers:

timofeeve [1]3 years ago

8 0

Answer:

The answer is any multiple of 36.

Step-by-step explanation:

A decagon has 10 sides, and it has 10 exterior angles of 36° as can be seen in the picture.

Therefore, by rotating the decagon about its center by multiples of 36° will carry a regular decagon onto itself.

Any multiple of 36 could be: 36, 72, 108, 144, 180, 216, 252, 288, etc...

snow_lady [41]3 years ago

3 0

A decagon has 10 sides so every 36 degrees, you would encounter another side.
So, the answer is a 36 degree rotation.

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What is the probability that a student chosen randomly from the class does not have a cat

Bas_tet [7]

Answer:

20/27 or 0.74

Step-by-step explanation:

The total number of people is: 2+6+5+14 = 27

Total number of people that don't have a cat is: 6+14 = 20

20/27 = 0.74

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2 years ago

Toby's piggy bank contains only 5c and 10c coins. If it contains 65 coins with a total value of 3.80, find the number of each ty

mr_godi [17]

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3 years ago

Need this asap, thanks in advance :)

sveticcg [70]

Answer:

non linear

Step-by-step explanation:

8 0

3 years ago

QUESTION 1

lukranit [14]

1.) 2368000 (two million, three hundred sixty-eight thousand)
2.) 864,346,000 rounded to nearest thousand
3.) 864,345,537.00 not 100% on the last answer

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2 years ago

What is the equation of a line perpendicular to y=-2/5X-1 that passes through (2,-8)

AysviL [449]

Answer:

$y=\frac{5}{2}x-13$

Step-by-step explanation:

Given the equation

$y=-\frac{2}{5}x-1$

comparing the equation with the slope-intercept form $y=mx+b$

Here,

m is the slope

b is the intercept

so the slope of the line is m = -2/5

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line,

so the slope of the perpendicular line will be: 5/2

Therefore, the point-slope form of the equation of the perpendicular line that goes through (2,-8) is:

$y-y_1=m\left(x-x_1\right)$

$y-\left(-8\right)=\frac{5}{2}\left(x-2\right)$

$y+8=\frac{5}{2}\left(x-2\right)$

subtract 8 from both sides

$y+8-8=\frac{5}{2}\left(x-2\right)-8$

$y=\frac{5}{2}x-13$

8 0

3 years ago