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2 years ago

How do u do this problem: W/6+5/8=-1 3/8 I got this answer: -1 53/64

2 answers:

6 0

We have question
$\frac{W}{6}+ \frac{5}{8} =-1 \frac{3}{8}$
$\frac{W}{6} + \frac{5}{8} =- \frac{11}{8}$ /*8 (multiply both sides by 8)
$\frac{W8}{6} + \frac{5}{1} =- \frac{11}{1}$ /*6 (multiply both sides by 6)
$8W+5*6=-11*6$ /-30 both sides
8W=-66-30
8W=-96
W=-12

emmainna [20.7K]2 years ago

5 0

Let's solve your equation step-by-step.w6+58=(−1)(3)8
Step 1: Simplify both sides of the equation.16w+58=−38
Step 2: Subtract 5/8 from both sides.16w+58−58=−38−5816w=−1
Step 3: Divide both sides by 1/6.16w16=−116w=−6
Answer:w=−6

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M,H, and G have written more than a combined total of 22 articles. H has written 1/4 as many as M. G has written 3/2 as M. Write

Natalka [10]

Missing part of the question:

Write an inequality to determine the number of articles, M could have written for the school newspaper.

Answer:

The inequality: $11M > 88$

The solution: $M > 8$

Step-by-step explanation:

Given

From the question, we have the following parameters:

$M + H + G > 22$

$H = \frac{1}{4}M$

$G = \frac{3}{2}M$

Required

Determine the inequality to solve for M

Substitute the values for H and G in the inequality:

$M + H + G > 22$

$M + \frac{1}{4}M + \frac{3}{2}M > 22$

Multiply through by 4

$4(M + \frac{1}{4}M + \frac{3}{2}M) > 22*4$

$4M + M + 6M > 88$

$11M > 88$

Divide both sides by 11

$M > 8$

4 0

2 years ago

PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

7 0

3 years ago

3/4-(-7/6) Write your answer in simplest form.

allsm [11]

Answer:

$\frac{3}{4} - ( - \frac{7}{6} ) \\ = \frac{3}{4} + \frac{7}{6} \\ = \frac{23}{12} \\ = 1 \frac{11}{12}$

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2 years ago

Michael has eight coins of all which are quarters and pennies and all there were $1.76 how many of each kind of coin does Michae

Tju [1.3M]

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3 years ago

Which of the following is the most profitable investment for a candy shop that earns $1 revenue per pound of candy? (5 points) G

rewona [7]

Then the most profitable investment is the first machine (third option) because for each dollar, it produces 2 pounds of candy.

<h3>Which of the following is the most profitable investment?</h3>

The first option is a worker that costs $10 per hour and produces 8lb, then this worker gives:

8lb/$10= 0.8 pounds per dollar.

The second worker costs $12 per hour, and produces 16lb per hour, so this worker gives:

16lb/$12 = 1.33 pounds per dollar.

The third option is a machine that cost $5 per hour and produces 10lb per hour, then:

10lb/$5 = 2 pound per dollar.

The last option costs $8 per hour, and produces 14 pounds per hour, then:

14lb/$8 = 1.75 pounds per dollar.

Then the most profitable investment is the first machine (third option) because for each dollar, it produces 2 pounds of candy.

If you want to learn more about profit:

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2 years ago