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3 years ago

4. Order the numbers from least to greatest. √5, 5, 2.5. Ja

Mathematics

1 answer:

lara31 [8.8K]3 years ago

8 0

Answer:

√5 < 2.5 < 5

Step-by-step explanation:

√5= 2.23

therefore,

√5 < 2.5 < 5

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The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31

4 0

3 years ago

The temperature in degrees Celsius can be determined using the expression 5 9 (F – 32) where F is the temperature in degrees Fah

Norma-Jean [14]

Answer:

The temperature on Celsius scale for 86 ºF is 30 ºC.

Step-by-step explanation:

Both degrees Celsius and Fahrenheit are relative scales of temperature. The relationship between degrees Fahrenheit and degrees Celsius is summarized by the equation below:

$T_{C} = \frac{5}{9}\cdot (T_{F}-32)$ (1)

Where:

$T_{F}$ - Temperature, measured in degrees Fahrenheit.

$T_{C}$ - Temperature, measured in degrees Celsius.

If we know that $T_{F} = 86\,^{\circ}F$ , then its equivalent temperature on Celsius scale is:

$T_{C} = \frac{5}{9}\cdot (86-32)$

$T_{C} = 30\,^{\circ}C$

The temperature on Celsius scale for 86 ºF is 30 ºC.

3 0

3 years ago

I need help on this question

AleksandrR [38]

11.84 rounded to the nearest whole number is 12. It’s simple add all c,d, and f percents. Then turn the percent into a decimal by dividing by 100, and multiply that decimal by the students , which is 32.

6 0

3 years ago

F(2) if f(x) = 2x - 5

Licemer1 [7]

Answer:

The answer is 4.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

How many times dies 11000 go into 609,000

diamong [38]

This is simply 609 000 divided by 11 000

609 000 / 11 000.

Cancel each of the 3 zeros at the top and bottom

= 609/11

Use a calculator

= 55.3636...

So it goes in approximately 55.36 times.

8 0

3 years ago