Consider the triangle with vertices (0, 0), (1, 0), (0, 1). Suppose that (X, Y ) is a uniformly chosen random point from this tr
iangle. (a) Find the marginal density functions of X and Y . (b) Calculate the expectations E[X] and E[Y ]. (c) Calculate the expectation E[XY ].
1 answer:
You might be interested in
Answer:
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Step-by-step explanation:
Given:
Let,
point S( x₁ , y₁) ≡ ( -1 , 1)
point T( x₂ , y₂) ≡ (3 , -5)
Point M( x , y ) is the Mid point of segment ST.
To Find:
Point M( x , y )= ?
Solution:
As Point M( x , y ) is the Mid point of segment ST.
So we have Mid Point Formula as
On substituting the given values in above equation we get
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Answer:
91
Step-by-step explanation:
85= then multiply the 4 over and subtract 80, 87, and 82 to find x which gives you 91