Which pair of complex factors results in a real number product? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)
2 answers:
Answer:
(4 + 7i)(4 – 7i)
Step-by-step explanation:
This pair will produce a real answer because they are complex conjugates.
Complex conjugates ( a+bi) (a-bi) when multiplied together form a real number ( a^2 + b^2)
Answer:
D. (4+7i)(4-7i)
Step-by-step explanation:
You might be interested in
Answer:
idk
Step-by-step explanation:
1/2
Is the answer
To the problem
Answer:
㏒e(x)= 5
Step-by-step explanation:
Answer:
your answer will be option d
Step-by-step explanation:
because cosine =base/hypotenus
and here 8/17
hope ur help
Answer:
is there a question?
Step-by-step explanation:
