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Rasek [7]
3 years ago
9

Which pair of complex factors results in a real number product? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)

Mathematics
2 answers:
photoshop1234 [79]3 years ago
6 0

Answer:

(4 + 7i)(4 – 7i)

Step-by-step explanation:

This pair will produce a real answer because they are complex conjugates.

Complex conjugates ( a+bi) (a-bi)  when multiplied together form a real number ( a^2 + b^2)

I am Lyosha [343]3 years ago
6 0

Answer:

D. (4+7i)(4-7i)

Step-by-step explanation:

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