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Yakvenalex [24]
4 years ago
9

Pls give me the answer ​

Mathematics
1 answer:
natima [27]4 years ago
5 0
49a²+14a18b+81b²

When you square a binomial, you have to multiply the entire thing by itself, so in this case it should be: (7a+9b) (7a+9b).

Now you have to use FOIL (or First, Outside, Inside, Last) to simplify the equation. When you set up FOIL, it should look like this:
7a×7a, 7a×9b, 7a×9b, 9b×9b. Simplify this and you should get 49a²+7a9b+7a9b+81b². Add like terms and you get 49a²+14a18b+81b².
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\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 6 + 19}\times6 \\ T_{20\text{ }}\text{ = 6 + 114} \\ T_{20\text{ }}\text{ = 120} \end{gathered}

2) 3,6,9,12

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 3, d = 3

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 3 + 19 }\times3 \\ T_{20\text{ }}\text{ = 3 + 57} \\ T_{20\text{ }}\text{ = 60} \end{gathered}

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The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 1, d = 4

\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 1 + 19 }\times4 \\ T_{20\text{ }}\text{ = }1\text{ + 76} \\ T_{20\text{ }}\text{ = }77 \end{gathered}

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