Answer:
subtract 2.5 on both sides
Answer:
Is the question to develop the equation for the straight line shown?
If so,<u> y = (3/4)x + b</u>
Step-by-step explanation:
Look for an equation with the form y = mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).
Calculate Slope using the Rise/Run.
Pick any two points. I chose (-4,0) and (4,6).
Going from left to right:
Rise = (6 - 0) = 6
Run = (4 - (-4)) = 8
Slope is Rise/Run, 6/8 or 3/4
So we have: y = (3/4)x + b
We can see that the y-intercept, b, is 3 (the value of y when x = 0).
The full equation becomes :<u> y = (3/4)x + 3 </u>
The angles of the triangle are given as to have measures of 45°-45°-90°. This entails that the triangle is an isosceles triangle where the 2 legs of the triangle are of equal length. We calculate as follows:
c² = a² + b²
c² = 2a²
4² = 2a²
a = 2√2
Hope this answers the question.
Line HK is the line of intersection between pllanes AMKH and HKDY.
Consider all given options:
1. Line PB is the line of intersection between pllanes APBM and PBDY. Since planes APBM || HKDY and AMKH || PBDY, then lines PB and HK are parallel.
2. Line AM is the line of intersection between pllanes APBM and AMKH. Since planes APBM || HKDY and parallel planes are cut by plane AMKH, then lines AM and HK are parallel.
3. Line YD is the line of intersection between pllanes HKDY and AMKH. Since planes AMKH || PBDY and parallel planes are cut by plane HKDY, then lines YD and HK are parallel.
4. Lines HA and HK intersect each other at point H, thus they are not parallel.
5. Lines BM and HK are not parallel, because MB || DK and DK intersect HK at point K.
Answer: correct choices are A, B, C.
