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katen-ka-za [31]
3 years ago
12

What percent of 94 is 47

Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0

Answer:

50%

Step-by-step explanation:

47 is half of 94 which is the same thing as 50% of 94

raketka [301]3 years ago
6 0

Answer:

94% of 47 is just 47 x 0.94 ¯\_(ツ)_/¯

So 44.18

Please mark brainliest which would help alot.

Step-by-step explanation:


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She has to donate 46 more 127 x 2 +n=300 You have to add 127 twice, which gives you 254. Then you subtract that from 300.
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Find the Perimeter of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenths place.
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Answer:

50.6

Step-by-step explanation:

The perimeter of the circle is 12.56 because we take 1/2 of 8 (the length of the short side of the rectangle) and multiply that by pie (or 3.14). Now that we know that the perimeter of the circle is 12.56 we add that to 8 (short side of the rectangle) and we add that to 15 twice (which is 30)

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If Josie runs a 25-mile race in 5 hours and Greta runs a 18-mile race in 4 hours. Who runs at a FASTER pace?
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Step-by-step explanation:

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KIA buys a shirt that cost $12.50 and some pairs of socks that are $2.50 each. She pays a total of $27.50. How many pairs of soc
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Please for the love of god anwser my question lay correctly I really need your help :( I will give 25 points :)! This is geometr
tangare [24]

Answer:

\displaystyle \rm  A_{ \text{c  - pentagon}} =41

\rm \displaystyle P _{ \rm c - pentagon} =  20+ 4 \sqrt{2}

Step-by-step explanation:

we have a square and a triangle

we want to figure out the area and the perimeter of the pentagon

to figure out the area of the pentagon we can use the given formula:

\displaystyle \rm  A_{ \text{c  - pentagon}} = A_{ \text{squre}} - A_{ \text{triangle}}

let's figure out A_{\rm square}:

since the given shape is a square Every angle of its 90° Thus the triangle is a right angle triangle

therefore the height is 4

\displaystyle A _{ \rm triangle} =  \frac{1}{2}  \times b \times h

substitute h and b

\displaystyle A _{ \rm triangle} =  \frac{1}{2}  \times 4 \times 4

reduce fraction:

\displaystyle A _{ \rm triangle} =   2 \times 4

simplify multiplication:

\displaystyle A _{ \rm triangle} =   8

likewise square

\displaystyle A _{ \rm squre} =  {s}^{2}

substitute s:

\displaystyle A _{ \rm squre} =  {7}^{2}

simplify square

\displaystyle A _{ \rm squre} =  49

hence,

\displaystyle \rm  A_{ \text{c - pentagon}} =49- 8

\displaystyle \rm  A_{ \text{c  - pentagon}} =41

to figure out perimeter

let's figure out hypotenuse first

\displaystyle h =  \sqrt{ {4}^{2}   +  {4}^{2} }

\displaystyle h =  \sqrt{ 16  +  16}

\displaystyle h = 4 \sqrt{2}

therefore,

\rm \displaystyle P _{ \rm c - pentagon} = 3 + 3 + 4 \sqrt{2}  + 7 + 7

\rm \displaystyle P _{ \rm c - pentagon} = 6 + 4 \sqrt{2}  + 14

\rm \displaystyle P _{ \rm c - pentagon} =  20+ 4 \sqrt{2}

5 0
3 years ago
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