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Serga [27]
2 years ago
11

Solve the equation. X- 8 = 12

Mathematics
2 answers:
beks73 [17]2 years ago
4 0

Answer:

garri49 [273]2 years ago
4 0

Answer :

  • X-8=12
  • X= 12-8
  • X= 4

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2x - 3y = 8 // <br><br> Find y
konstantin123 [22]

Answer:

y = -\frac{2}{3} x - \frac{8}{3}

Step-by-step explanation:

2x - 3y = 8\\

Isolate y

-3y = 8-2x\\-3y = -2x+8

Divide both sides of the equation by -3

\frac{-3y}{-3} = \frac{2x}{-3} +\frac{8}{-3} \\\\y = -\frac{2}{3} x - \frac{8}{3}

7 0
3 years ago
Give the probability that the spinner shown would land on the indicated color:1) black
mel-nik [20]
There is not enough information to answer :(
5 0
3 years ago
Plzzzzz help i'm in desprate need of help with this
Ainat [17]

Answer:

Obtuse

Step-by-step explanation:

Right = has angle measure of 90°

Acute = has angle measure less than 90°

Equilateral = 2 or more angles whose angle measures are congruent to others

Circle = measures 360°

<u>Obtuse = Angle measure greater than 90° and less than 180°</u>

Hope this helps!

5 0
3 years ago
What is the lcm of 6 and 4
IceJOKER [234]

12 The least common multiple of 6 and 4 is 12

3 0
3 years ago
Read 2 more answers
Let c be parametrized by x = et sin (10t) and y = et cos (10t) for 0 ≤ t ≤ 2. find the length l of
marysya [2.9K]
C:x(t)=e^t\sin10t;\,y(t)=e^t\cos10t;\,0\le t\le2

\displaystyle\int_0^2\sqrt{x'(t)^2+y'(t)^2}\,\mathrm dt
\displaystyle=\int_0^2\sqrt{(e^t\sin10t+10e^t\cos10t)^2+(e^t\cos10t-10e^t\sin10t)^2}\,\mathrm dt
\displaystyle=\int_0^2e^t\sqrt{\sin^210t+20\sin10t\cos10t+100\cos^210t+\cos^210t-20\sin10t\cos10t+100\sin^210t}\,\mathrm dt
=\displaystyle\int_0^2e^t\sqrt{1+100}\,\mathrm dt
=\displaystyle\sqrt{101}(e^2-1)
7 0
3 years ago
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