Answer: The answer is $\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.$

Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.

Let the other root of the equation be 'p'. So, we have

$p-5=-\dfrac{7}{3}\\\\\\\Rightarrow p=5-\dfrac{7}{3}\\\\\\\Rightarrow p=\dfrac{8}{3},$

and

$p\times(-5)=-\dfrac{q}{3}\\\\\\\Rightarrow \dfrac{8}{3}\times 5=\dfrac{q}{3}\\\\\\\Rightarrow q=40.$

Thus, the other root is $\dfrac{8}{3}$ and the value of 'q' is 40.

3 0

3 years ago

If 2^2x = 2^3, what is the value of x?

Advocard [28]

Answer:

x=3/2

Step-by-step explanation:

2^2x=2^3

2x=3

x=3/2

6 0

3 years ago

Graphing this equation -x+4y=8

Keith_Richards [23]

The linear form of that equation is y=1/4x+2. Your y-intercept should be 2 and the slope is 1/4.

8 0

3 years ago

Please tell me the right answer.

Komok [63]

Answer:

Step-by-step explanation:

7 0

3 years ago

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